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Kitty [74]
3 years ago
7

Find dy/dx by implicit differentiation: 4 cos x sin y = 2

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0
Hello,

f(x,y)=4cos x sin y-2

@f/@x=-4sin x sin y

@f/@y=4 cos x cos y

dy/dx=-(@f/@x)/(@f/@y)=sin x sin y/(cos x cos y)=tg x * tg y
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Several paint mixtures are made by mixing blue paint and white paint. Paint Colors Blue Paint White Paint Mixture A 5 cups 12 cu
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The correct answer is option B which is mixture B will have the highest ratio of blue paint.

<h3>What is a ratio?</h3>

In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

<h3 />

The given ratios are:-

Mixture A = \dfrac{5}{12} = 0.41

Mixture B = \dfrac{6}{6}= 1

Mixture C = \dfrac{4}{12}= 0.33

Mixture B = \dfrac{5}{6}=0.83

Here the ratio of mixture B is the highest among all the options available.

Therefore the correct answer is option B which is mixture B will have the highest ratio of blue paint.

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All whole numbers are integers, and all integers are also whole numbers.
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Those are adjacent angles. They equal 180 degrees. 

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A theater has 500 seats. Three fourths of the seats are filled how many seats are filled
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A theater has 500 seats. Three fourths of the seats are filled how many seats are filled

375 seats are filled

4 0
3 years ago
At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
3 years ago
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