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3 years ago

11

What is the equation of the line that passes through the point (-4,-6) and has a slope of -1/2?

1 answer:

Mariulka [41]3 years ago

6 0

Answer:

y + 6 = -1/2(x + 4)

y + 6 = -1/2x - 2

y = -1/2x - 8

Step-by-step explanation:

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V / -0.8 +14=39 plssss help this is literally so hard

Nat2105 [25]

<h2><u>Answer:</u></h2><h2> $\boxed{\boxed{\sf~v=-20}}$ </h2><h2 /><h2><u>Solution Steps:</u></h2>

______________________________

<h3>1.) Subtract 14 from both sides:</h3>

$14-14=$ Cancels Out

$39-14=25$

<em> - We do this because we have to get 2 variables/numbers on each side of the equals, and the only way to do so is to cancels other numbers out by doing the opposite of what we see. </em>

<u>Equation at the end of Step 1: </u>

$v$ ÷ $-0.8=25$

<h3>2.) Multiply both sides by −0.8:</h3>

$-0.8$ × $-0.8=$ Cancels Out

$25$ × $-0.8=-20$

______________________________

3 0

3 years ago

Quickly compute the following differences of squares. (a). 64^2 − 14^2 (b). 112^2 − 88^2 (c). 785^2 − 215^2

VikaD [51]

Answer:

(a) 3900

(b) 4800

(c) 570000

Step-by-step explanation:

We have given

(a) $64^2-14^2$

We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

So $64^2-14^2=(64+14)(64-14)=3900$

(b) We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

$112^-88^2=(112+88)(112-88)=4800$

(c) We know the algebraic equation $a^2-b^2=(a+b)(a-b)$

$785^2-215^2=(785+215)(785-215)=570000$

5 0

3 years ago

A bike shop selected 20 people at random from a population of 426 customers and asked each how many bicycles there are at that p

Vitek1552 [10]

Thank you for posting your question here at brainly. Feel free to ask more questions.
<span>
The best and most correct answer among the choices provided by the question is A </span>2.
  <span>
Hope my answer would be a great help for you.  </span>

3 0

3 years ago

The perimeter of a rectangle is 42 inches. If the width of the rectangle is 9 inches, what is the length?

Leona [35]

Answer:

12 inches

Step-by-step explanation:

let length be L

formula for perimeter of rectangle = 2( length + width )

2( L + 9) = 42

2L + 18 = 42

2L = 24

L = 12 inches

8 0

2 years ago

Read 2 more answers

Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten

serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

$\frac {dN}{dt}\propto -N$

$\Rightarrow \R\frac {dN}{dt}=-\lambda N$

$\Rightarrow \frac {dN}N=-\lambda dt$

Integrating both sides

$\Rightarrow \int \frac {dN}N=\int-\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$ln|N_0|=-\lambda .0+c$

$\Rightarrow c=ln|N_0|$

$ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$

Decay equation:

$ln|\frac{N}{N_0}|=-\lambda t$

Given that, the half life of of element X is 11 minutes.

For half life, $N=\frac12 N_0$ , t= 11 min.

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11$

$\Rightarrow ln|\frac12}|=-\lambda . 11$

$\Rightarrow -\lambda . 11=ln|\frac12}|$

$\Rightarrow \lambda =\frac{ln|\frac12|}{-11}$

$\Rightarrow \lambda =\frac{ln|2|}{11}$ [ $ln|\frac12|=ln|1|-ln|2|=-ln|2|$ , since ln|1|=0]

N=154 grams, $N_0$ = 870 grams, t=?

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t$

$\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}$

=27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0

3 years ago