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elena55 [62]
3 years ago
11

What is the volume of the triangular prism below?

Mathematics
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

4.5 ft

Step-by-step explanation:

18 inches = 1.5 ft

\frac{1}{2}  \times 1.5 \times 2 \times 3 = 4.5

Volume of triangular prism = Base Area x Length

Hope this helps

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faltersainse [42]

Answer:

Cost of bicycle. £403.50

His present savings. £265.90

Amount required. £137.60

Step-by-step explanation:

pls brain list I hope I helped

3 0
3 years ago
Which of the following has no solution?
Sholpan [36]
The first one.
This statement is saying that x is less than zero and greater than zero at the same time. This is not possible. A number cannot be both negative and positive.
It's not the second one because this one includes equal to zero. It can be lass than or equal to zero and greater that or equal to zero because it can be ZERO.
It's not the third because this one is an OR statement. It can be less than or equal to zero OR greater than or equal to zero.
I hope you understand
8 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
Basile [38]

The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

brainly.com/question/14487937

#SPJ4

6 0
1 year ago
A student wants to simulate 31 ​birthdays, but she does not have a calculator or software program​ available, so she makes up 31
mihalych1998 [28]

Answer:

No, it is not okay to conduct the simulation this​ way.

Step-by-step explanation:

In statistics, simulation refers to a technique that is employed to model random events so that the results obtained from using the simulation is significantly similar to the results obtained from observing the real-world.

Researchers are therefore able to understand the real world when they observe the simulated outcomes.

From the description above, it can be seen that simulation is about studying random events. Therefore, a sample of the population that will be used in the simulation must be selected through a random sampling.

Random sampling refers to the sampling method that gives equal opportunity of being selected to each member of the population. This makes the sample selected through random sampling technique to be an unbiased representation of the total population.

As a result, making up 31 numbers between 1 and 365 by the student is not a random sampling, because his method may favor some numbers over others. It is therefore a defective method of carrying out simulation.

 Therefore, the it is not okay to conduct the simulation this​ way.

I wish you the best.

6 0
3 years ago
How many significant figures are there In the number 10.76
lana66690 [7]

Answer:

Number of Significant Figures: 4

The Significant Figures are 1 0 7 6

5 0
2 years ago
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