Answer:
bottom left corner
Step-by-step explanation:
Answer:
The answer in the procedure
Step-by-step explanation:
we know that
The rule of the reflection of a point over the y-axis is equal to
A(x,y) ----->A'(-x,y)
That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same
so
A(3,-1) ------> A'(-3,-1)
The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)
therefore
To reflect a point over the y-axis
Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis
Put the value of x = -2 to the equation of the function y = -4x + 3:
y = -4(-2) + 3 = 8 + 3 = 11
<h3>Answer: A. (-2, 11)</h3>
Answer:
y + 7 = (x + 6)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
Here m = and (a, b ) = (- 6, - 7 ) , then
y - (- 7) = (x - (- 6) ) , that is
y + 7 = (x + 6)