The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Since 3in, 4in, and 8in. Since 6+14 > 10,6+ 10 > 14, and 10 + 14 > 6, you can form a triangle with the lengths 6m, 14m, and 10m.
-3/5x + 1/5 > 7/20
-3/5x > 7/20 - 1/5
-3/5x > 7/20 - 4/20
-3/5x > 3/20
x < 3/20 * - 5/3
x < -15/60 reduces to -1/4
