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3 years ago

Resssspooond quickkk

Mathematics

2 answers:

aev [14]3 years ago

8 0

See attachment file below.

Hope it helped!

Doss [256]3 years ago

7 0

The slope of the given line is -1/3. The perpendicular line's slope is the opposite reciprocal of the given line's slope. So, the perpendicular line's slope is 3. Then we have slope intercept form y=mx+b

y=3x+b
We don't know "b" which is the y-intercept for this equation, but we have the coordinates (6, -1). We can use these to find the slope by plugging them into the equation.

-1=3(6)+b
-1=18+b
-1-18=18+b-18
-19=b
So, the resulting y-intercept is -19.

The final perpendicular equation would be y=3x-19

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faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

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$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

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$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

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$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

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2 years ago

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hope this helps!:)

Step-by-step explanation:

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3 years ago