Question

The following statistics represent weekly salaries at a construction company.

Answer 1

Answer:

The most common salary is $605. The salary that half the employees salaries surpass is $630. The percent of employees salary that serve because $700 is 75%. Percent of employees salaries that were less than $480 is 25%. The 9% percent of employees salaries this surpass $891 years. The total weekly salary of 104 employees is 57200.

Step-by-step explanation:

It is given that mean is $550, first quartile is $480,  median is $630, third quartile is $700,  mode is $605 and 91st percentile is $891.

First quartile is at 25% of the data, median is at 50% of the data, third quartile is at 75% of the data.

The mode of a set of data values is the value that occurs most often.

The most common salary is mode, therefore the most common salary is $605.

The salary that half the employees salaries surpass is $630. Because median is the half of the data.

The percent of employees salary that serve because $700 is 75%. Because $700 is third quartile.

Percent of employees salaries that were less than $480 is 25%. Because $480 is first quartile.

The percent of employees salaries this surpass $891 years is 9%. Because $891 is 91 percentile. Therefore 9% employees get more than $891.

If the company has 104 employees than the total salary of employees is

$104\times 550=57200$

because means is $550, therefore the total weekly salary of 104 employees is 57200.

Answer 2

The most common salary.....this is ur mode = 605
the salary that half employees surpass.....this is ur median = 630
percent of employees salary that serve because 700 is 75%
percent of employees salary less then 480 is 25%
percent of employees salary that surpass 891 = 9%
sorry, I do not know the last one

** the mode is a number that appears most often, the most common
Q1 = 25% of data
Q2(middle) = 50% of data
Q3 = 75% of data