Answer: $9.50
Step-by-step explanation:Let's define the variables:
A = price of one adult ticket.
S = price of one student ticket.
We know that:
"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."
1*A + 6*S = $69
"The school took in $150 on the second day by selling 7 adult tickets and student tickets"
7*A + 7*S = $150
Then we have a system of equations:
A + 6*S = $69
7*A + 7*S = $150.
To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:
A = $69 - 6*S
Now let's replace this in the other equation:
7*($69 - 6*S) + 7*S = $150
Now we can solve this for S.
$483 - 42*S + 7*S = $150
$483 - 35*S = $150
$483 - $150 = 35*S
$333 = 35*S
$333/35 = S
$9.51 = S
That we could round to $9.50
That is the price of one student ticket.
This is an arithmetic sequence because each term is 7 greater than the previous term, so 7 is what is called the common difference...
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=first term, d=common difference, n=term number.
We know a=1 and d=7 so:
a(n)=1+7(n-1)
a(n)=1+7n-7
a(n)=7n-6
The above is the "rule" for the nth term.
Answer:
10x + 35
Step-by-step explanation:
Answer:
Step-by-step explanation:
SEARCH IT UP!!!!!!!
Answer:
Average rate of change over the interval 2<= x <= 5:
y = 3x + 5: 3
y = 3x^2 + 1: 21
y = 3^x: 78
<u />
Step-by-step explanation:
2<= x <= 5
Average rate of change over the interval 2<= x <= 5:
<u>y = 3x + 5</u>
y(5) = 3(5) + 5 = 20
y(2) = 3(2) + 5 = 11
Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>
<u />
<u>y = 3x^2 + 1</u>
y(5) = 3(5^2) + 1 = 75 + 1 = 76
y(2) = 3(2^2) + 1= 13
Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>
<u />
<u>y = 3^x</u>
y(5) = 3^5 = 243
y(2) = 3^2 =9
Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>
