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MAXImum [283]
3 years ago
9

A store owner paid 15 dollars for a book. She marked up the price of the book by 40 percent to determine its selling price.

Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0
Part a: 21 dollars because you multiply .40 with 5 and get 6. you add the 6 to the 15 and get 21.
part b: 30.21 because you multiply 38 by .25 and get the answer for that and then subtract that number from 38. then you multiply 0.06 by 38 and when u get that number, add that to the discounted price.
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HELPPP
Mazyrski [523]

Answer:

Hello,

Step-by-step explanation:

y-intercept: x=0 ,f(0)=-10

x^3-8x^2+17x-10\\\\=x^3-5x^2-3x^2+15x+2x-10\\\\=x^2(x-5)-3x(x-5)+2(x-5)\\\\=(x-5)(x^2-3x+2)\\\\=(x-5)(x^2-x-2x+2)\\\\=(x-5)(x(x-1)-2(x-1))\\\\=(x-5)(x-1)(x-2)\\

x-intercepts are: 5,1,2.

6 0
3 years ago
3x + 1 = 5X-13 if anyone knows what to do can they please help ​
Elza [17]

Answer:

  x = 7

Step-by-step explanation:

First, you look at the equation. Identify the locations of variable terms (both sides of the equal sign) and the constant terms (both sides of the equal sign).

If there are any parentheses, it is a good idea to use the distributive property to eliminate them. Here, there are none.

I like to start by subtracting <em>the variable term with the smallest coefficient</em>. Here, that is 3x, so we add -3x to both sides of the equation.

  3x -3x +1 = 5x -3x -13

  1 = 2x -13 . . . . . . . . . . . . combine like terms

Now, we have the only variable term on one side of the equal sign. We want it by itself, so we need to make the -13 go away. We do that by adding its opposite to both sides of the equation:

  1 +13 = 2x -13 +13

  14 = 2x . . . . . . . . . . . . combine like terms

Finally, we want the coefficient of 2 in the x-term to disappear. We make that happen by multiplying both sides of the equation by 1/2, the reciprocal of that coefficient.

  (1/2)(14) = (1/2)(2x)

  7 = x . . . . the solution

__

It is generally a good idea to <em>check your work</em> by seeing if your solution value satisfies the equation:

  3(7) +1 = 5(7) -13 . . . . put 7 where x is in the original equation

  21 +1 = 35 -13

  22 = 22 . . . . . . x = 7 is the solution

_____

<em>Additional comment</em>

By subtracting 3x from 5x, the result is 2x with a positive coefficient. We could solve the equation just as easily by subtracting 5x from 3x. That result would be ...

  -2x +1 = -13

Subtracting 1 would give

  -2x = -14

and you would multiply by -1/2 to get x=7. I personally like to avoid having this many minus signs show up in the problem. That is why I choose to subtract the x-term with the smallest coefficient.

5 0
3 years ago
In a group of 33 students, 7 study both Art and Biology. 10 study Biology but not Art. 7 study neither subject. How many study A
netineya [11]

Answer:

9

Step-by-step explanation:

4 0
3 years ago
Uhhhhh.....help is needed.
bulgar [2K]

Answer:

D.

Step-by-step explanation:

Look for the closed circle with the arrow pointing to the right on this one.

5 0
3 years ago
Read 2 more answers
The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0
3 years ago
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