All categories

3 years ago

PLS HELP I NEED TO FIND THE ACTUAL DISTANCE BETWEEN WACH OAIR IF CITIES AND IF NECESSARY I HAVE TO ROUND TO THE NEAREST TENTH

Mathematics

1 answer:

kolbaska11 [484]3 years ago

8 0

1; 127 mi

2;78

Sorry i did not know the other answers

I hoped this helped

You might be interested in

Un empresario textil de Gamarra desea distribuir un bono de productividad entre sus empleados por su buen desempeño en la semana

spin [16.1K]

Answer:

There are 6 employees in the factory

The amount of money distributed to the employees = 5000 soles

To solve the problem without using equations, We would try different numbers for the employees starting from 2 employees.

Question:

A textile entrepreneur from Gamarra wants to distribute a productivity bonus among his employees for his good

performance in the week. Making calculations, he realizes that if he gave each one 800 soles, he would have

200 leftovers , and if he gave them 900 soles, he would lack 400. How many employees are there in your factory? How much money do you have to distribute? How would you solve the problem without using equations?

Step-by-step explanation:

For the first two questions, we would determine the number of employees that are in the factory and the amount of money that was distributed by solving using equations. Each statement would be written in the form of an equation.

Let the amount of money distributed to the employees = p

The number of employees in the factory = q

First statement showing the relationship of the variables:

800q + 200 = p ...equation 1

2nd statement showing the relationship of the variables:

900q - 400 = p ...equation 2

Equating both equations: p = p

800q + 200 = 900q - 400

900q-800q = 200+400

100q = 600

q = 600/100 = 6

Substitute for q = 6 in any if the equation.

Using equation 1

800(6) + 200 = p

p = 5000

Therefore, the amount of money distributed to the employees = 5000soles

The number of employees in the factory = 6

To solve the problem without using equations, We would try different numbers for the employees starting from 2 employees (as they are more than 1) to arrive at a particular amount distributed:

(800×2) + 200 = 1800

(900×2) - 400 = 1400

By increasing the numbers using consecutive even numbers (2,4,6...) and multiplying, we would arrive at a value that is equal to both.

8 0

3 years ago

??? Help me with my work pls

serious [3.7K]

Answer:

2. 10 + 5 x 2 $20

3. 10 + 5 x 3 $25

4. 10 + 5 x 4 $30

Hope that helps!

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What number do you add to get from -6250 to -10

Tomtit [17]

You add 6240 to get from -6250 to -10 your welcome

3 0

3 years ago

A giant tank in a shape of an inverted cone is filled with oil. the height of the tank is 1.5 metre and its radius is 1 metre. t

skad [1K]

The given height of the cylinder of 1.5 m, and radius of 1 m, and the rate

of dripping of 110 cm³/s gives the following values.

1) The rate of change of the oil's radius when the radius is 0.5 m is r' ≈ 9.34 × 10⁻⁵ m/s

2) The rate of change of the oil's height when the height is 20 cm is h' ≈ 1.97 × 10⁻³ m/s

3) The rate the oil radius is changing when the radius is 10 cm is approximately 0.175 m/s

<h3>How can the rate of change of the radius & height be found?</h3>

The given parameters are;

Height of the tank, h = 1.5 m

Radius of the tank, r = 1 m

Rate at which the oil is dripping from the tank = 110 cm³/s = 0.00011 m³/s

$1) \hspace{0.15 cm}V = \frac{1}{3} \cdot \pi \cdot r^2 \cdot h$

From the shape of the tank, we have;

$\dfrac{h}{r} = \dfrac{1.5}{1}$

Which gives;

h = 1.5·r

$V = \mathbf{\frac{1}{3} \cdot \pi \cdot r^2 \cdot (1.5 \cdot r)}$

$\dfrac{d}{dr} V =\dfrac{d}{dr} \left( \dfrac{1}{3} \cdot \pi \cdot r^2 \cdot (1.5 \cdot r)\right) = \dfrac{3}{2} \cdot \pi \cdot r^2$

$\dfrac{dV}{dt} = \dfrac{dV}{dr} \times \dfrac{dr}{dt}$

$\dfrac{dr}{dt} = \mathbf{\dfrac{\dfrac{dV}{dt} }{\dfrac{dV}{dr} }}$

$\dfrac{dV}{dt} = 0.00011$

Which gives;

$\dfrac{dr}{dt} = \mathbf{ \dfrac{0.00011 }{\dfrac{3}{2} \cdot \pi \cdot r^2}}$

When r = 0.5 m, we have;

$\dfrac{dr}{dt} = \dfrac{0.00011 }{\dfrac{3}{2} \times\pi \times 0.5^2} \approx 9.34 \times 10^{-5}$

The rate of change of the oil's radius when the radius is 0.5 m is r' ≈ 9.34 × 10⁻⁵ m/s

2) When the height is 20 cm, we have;

h = 1.5·r

$r = \dfrac{h}{1.5}$

$V = \mathbf{\frac{1}{3} \cdot \pi \cdot \left(\dfrac{h}{1.5} \right) ^2 \cdot h}$

r = 20 cm ÷ 1.5 = $13.\overline3$ cm = $0.1\overline3$ m

Which gives;

$\dfrac{dr}{dt} = \dfrac{0.00011 }{\dfrac{3}{2} \times\pi \times 0.1 \overline{3}^2} \approx \mathbf{1.313 \times 10^{-3}}$

$\dfrac{d}{dh} V = \dfrac{d}{dh} \left(\dfrac{4}{27} \cdot \pi \cdot h^3 \right) = \dfrac{4 \cdot \pi \cdot h^2}{9}$

$\dfrac{dV}{dt} = \dfrac{dV}{dh} \times \dfrac{dh}{dt}$

$\dfrac{dh}{dt} = \dfrac{\dfrac{dV}{dt} }{\dfrac{dV}{dh} }$

$\dfrac{dh}{dt} = \mathbf{\dfrac{0.00011}{\dfrac{4 \cdot \pi \cdot h^2}{9}}}$

When the height is 20 cm = 0.2 m, we have;

$\dfrac{dh}{dt} = \dfrac{0.00011}{\dfrac{4 \times \pi \times 0.2^2}{9}} \approx \mathbf{1.97 \times 10^{-3}}$

The rate of change of the oil's height when the height is 20 cm is h' ≈ 1.97 × 10⁻³ m/s

3) The volume of the slick, V = π·r²·h

Where;

h = The height of the slick = 0.1 cm = 0.001 m

Therefore;

V = 0.001·π·r²

$\dfrac{dV}{dr} = \mathbf{ 0.002 \cdot \pi \cdot r}$

$\dfrac{dr}{dt} = \mathbf{\dfrac{0.00011 }{0.002 \cdot \pi \cdot r}}$

When the radius is 10 cm = 0.1 m, we have;

$\dfrac{dr}{dt} = \dfrac{0.00011 }{0.002 \times \pi \times 0.1} \approx \mathbf{0.175}$

The rate the oil radius is changing when the radius is 10 cm is approximately 0.175 m

Learn more about the rules of differentiation here:

brainly.com/question/20433457

brainly.com/question/13502804

3 0

3 years ago

Is it possible for 3 to go into 32

posledela

Yes. By all means yes. Its very very possible. In fact it can go in there ten times over.

3 0

4 years ago

Read 2 more answers