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julia-pushkina [17]
3 years ago
15

What is the simplified expression for -2a^2b+a^2-5ab+3ab^2-b^2+2(a^2b+2ab)​

Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer:

Step-by-step explanation:

Hello,

-2a^2b+a^2-5ab+3ab^2-b^2+2(a^2b+2ab)\\\\=-2a^2b+a^2-5ab+3ab^2-b^2+2a^2b+4ab\\\\=a^2+3ab^2-ab-b^2

Thanks

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Find the confidence interval with a 90% level of confidence. In October 2010, Gallup Poll asked 510 randomly sampled adults the
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Answer:

90% confidence interval for the percent of the population who consider the death penalty to be "fair" is [54.4% , 61.6%].

Step-by-step explanation:

We are given that in October 2010, Gallup Poll asked 510 randomly sampled adults the question, "Generally speaking, do you believe the death penalty is applied fairly or unfairly in this country today?"

Of these, 58% answered "fairly", 36% said "unfairly" and 7% said they didn't know.

Firstly, the Pivotal quantity for 90% confidence interval for the population proportion is given by;

                              P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion who answered death penalty "fair" = 58%

           n = sample of adults = 510

           p = population percentage

<em>Here for constructing 90% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 90% confidence interval for the population percentage, p is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                   of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.645) = 0.90

P( -1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \hat p-p < 1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

P( \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

<u>90% confidence interval for p</u> = [\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ,\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

             = [ 0.58-1.645 \times {\sqrt{\frac{0.58(1-0.58)}{510} } } , 0.58+1.645 \times {\sqrt{\frac{0.58(1-0.58)}{510} } } ]

             = [0.544 , 0.616]

Therefore, 90% confidence interval for the percent of the population who consider the death penalty to be "fair" is [54.4% , 61.6%].

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3 years ago
The ages of commercial aircraft are normally distributed with a mean of 13.5 years and a standard deviation of 7.3 years. what p
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Answer: The percent higher is 41.68%. If 49 planes were selected, 20 of them should be above 15 years.

To find the percent, we first need the z-score.

(15 - 13.5) / 7.3 = 0.21

Now, use a normal distribution table to find the percent above a score of 0.21. It will be 41.68%.

To find the number of 49 planes above this value, multiply 49 by 0.4168. You will have about 20.4 planes.
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Graph the inequality 3x+y≥-7
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Answer:

x≥ -7 x -y/3

Step-by-step explanation:

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3 years ago
61 = r/3 − 7 what is r
WINSTONCH [101]

Answer: r = -244

Step-by-step explanation:

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3 years ago
A 64-foot tall monument casts a shadow 16 feet long. If Kyle is stsnding nearby and is 6'3 tall, find the length of his shadow.​
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Answer: Length of his shadow is 18 feet.

Step-by-step explanation:

Since we have given that

Length of tall monument = 64 foot

Length of shadow = 16 feet

Length of pole where Kyle is standing = 6 feet 3 inch = 72 inches

So, we need to find the length of its shadow.

So, according to question, we get that

\dfrac{64\times 12}{16\times 12}=\dfrac{72}{x}\\\\4=\dfrac{72}{x}\\\\4x=72\\\\x=\dfrac{72}{4}\\\\x=18\ feet

Hence, length of his shadow is 18 feet.

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3 years ago
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