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ser-zykov [4K]
3 years ago
5

A slow jogger runs a mile in 11 minutes. Calculate the speed in km/h

Chemistry
1 answer:
emmasim [6.3K]3 years ago
3 0
By definition,
speed = dstance/time.

Note that
1 mile = 1.609 km


Therefore,
1 mile = 1.609 mk
11 minutes = 11/60 h = 0.1833 h

speed = (1.609 km)/(0.1833 h) = 8.78 km/h

Answer: 8.8 km/h (nearest tenth)
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It would be 10kg, because 1kg = 10N
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4 years ago
What is wrong with the following structure H-H-O
Strike441 [17]

Answer:

O atom requires 2 electrons to achieve octet structure and in this structure, it is only bonded to one H atom hence only obtaining an additional valence electron. Without a octet structure, the molecule is unstable hence this structure is incorrect. The correct structure should be H-O-H.

Explanation:

6 0
3 years ago
I need Help ASAP!!! I'M HAVING A FULL MELTDOWN plz and thank you<3
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7 0
3 years ago
Write electron configurations for Gallium, Ga (Z=31), and show the total valence electrons
ivann1987 [24]

<u>Answer:</u> The electronic configuration of gallium is written below and number of valence electrons is 3.

<u>Explanation:</u>

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

Valence electrons are defined as the electrons present in the outermost shell of an atom.

We are given:

An element Gallium having atomic number as 31.

Number of electrons = 31

Electronic configuration of Gallium is: (Z=31):1s^22s^22p^63s^23p^64s^23d^{10}4p^1

This element has 3 electrons in its outermost shell. So, the number of valence electrons is 3

Hence, the electronic configuration of gallium is written below and number of valence electrons is 3.

3 0
4 years ago
How many liters of 0.3m h3po4 are needed to neutralize 3.5l of 3m naoh
irga5000 [103]

Answer:

V_{acid}=11.7L

Explanation:

Hello,

In this case, given the reaction:

3NaOH+H_3PO_4\rightarrow Na_3PO_4+3H_2O

We notice a 3:1 molar ratio between sodium hydroxide and phosphoric acid, therefore, at the equivalence point we have:

n_{base}=3*n_{acid}

That in terms of molarity is:

M_{base}V_{base}=3*M_{acid}V_{acid}

Se we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{3*M_{acid}} =\frac{3M*3.5L}{3*0.3M}\\ \\V_{acid}=11.7L

Best regards.

4 0
3 years ago
Read 2 more answers
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