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3 years ago

Write down the names of compounds represented by the following formulae:

Chemistry

1 answer:

Angelina_Jolie [31]3 years ago

8 0

A-Aluminium sulphate.
B-Calcium Chloride.
C-Potassium sulphate.
D-Potassium Nitrate .
E-Calcium Carbonate.

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Using the standard reduction potentials, Pb 2+(aq) + 2e– => Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– => Fe(s), E° = –0.44 V Zn

mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$

Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with $E_{red}^{0}$ value lower than 1.51 V will donate electron to $Mn^{3+}$ and thus reduces $Mn^{3+}$ to $Mn^{2+}$ .

So, Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$ .

Metal with $E_{red}^{0}$ value lower than -0.40 V will donate electron to $Cr^{3+}$ and thus reduces $Cr^{3+}$ to $Cr$ .

So, Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$ .

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3 years ago

If 2.03 g of oxygen react with carbon monoxide, how many grams of CO2 are formed?

mamaluj [8]

Answer:

The suitable equation for this reaction is

2CO + O₂ -----> 2CO₂

Here, we are given that we have 2 grams of O₂

From the equation, we can see that 2 * Moles of O₂ = Moles of CO₂

Moles of O₂:

2/32 = 1/16 moles

Therefore, the number of moles of CO₂ is twice the moles of O₂

Moles of CO₂ = 2 * 1/16

Moles of CO₂ formed = 1/8 moles

Mass of CO₂ formed = Molar mass of CO₂ * Moles of CO₂

Mass of CO₂ formed = 44 * 1/8

Mass of CO₂ formed = 5.5 grams

Hence, option B is correct

Kindly Mark Brainliest, Thanks!!!

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3 years ago

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melomori [17]

Answer:

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3455

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3 years ago

What is the empirical formula for glucose<br> A)<br> B)<br> C)<br> D)

pshichka [43]

The Answer is A CH2O

The molecular formula for glucose is C6H12O6. The subscripts represent a multiple of an empirical formula. To determine the empirical formula, divide the subscripts by the GCF of 6 which gives CH2O.

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3 years ago

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Sodium is reacted with chlorine to produce sodium chloride. How much sodium chloride is produced when 45 grams of sodium reacted

77julia77 [94]

Answer:

114.7g

Explanation:

Given parameter:

Mass of Na = 45g

Unknown:

Mass of produced NaCl = ?

Solution:

The reaction equation is shown below;

2Na + Cl₂ → 2NaCl

Now, we solve from the known to the unknown. The known here is the mass of Na and it is sufficient to solve the problem;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Na = 23g/mol

Number of moles = $\frac{45}{23}$ = 1.96moles

2 mole of Na produced 2 moles of NaCl

1.96 moles of Na will produce 1.96 moles of NaCl

Mass of NaCl = number of moles x molar mass

= 1.96 x [23 + 35.5]

= 114.7g

5 0

3 years ago