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Anarel [89]
4 years ago
5

What is the number of moles and the mass of Mg required to react with 7.50g of HCl and produce MgCl2 and H2? 1.25 g 2.50 g 5.00

g
Chemistry
1 answer:
boyakko [2]4 years ago
4 0

Answer:

The correct option is: 2.50 g

Explanation:

Reaction involved: Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)

Molar mass: Mg = 24.305 g/mol, HCl = 36.461 g/mol

In the given reaction, 1 mole Mg reacts with 2 moles HCl.

Given: mass of HCl = 7.50 g

So, the number of moles of HCl = given mass ÷ molar mass = 7.50 g ÷ 36.461 g/mol = 0.2057 moles

Therefore, the<u> number of moles of Mg</u> that reacts with 0.2057 mole HCl = 0.2057 ÷ 2 = 0.1028 moles

Therefore, <u>the mass of Mg in grams</u> = molar mass × number of moles = 24.305 g/mol × 0.1028 mole = 2.5 g

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