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klemol [59]
3 years ago
10

If 1.85 g of Mg(OH)2 reacts with 3.71 g of HCl,

Chemistry
1 answer:
Damm [24]3 years ago
8 0
Both of them are a hope this helps
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How can I lucid dream?
xxMikexx [17]

Answer:

Set an alarm for five hours after your bedtime.

Go to sleep as usual.

When the alarm goes off, stay up for 30 minutes. Enjoy a quiet activity like reading.

Fall back asleep.

Explanation:

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3 years ago
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a ball with a mass of 20 kg is accelerating at 4 m/s/s while being thrown . about how much force was used to throw the ball
marta [7]

Answer:

<h2>80 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 20 × 4

We have the final answer as

<h3>80 N</h3>

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3 years ago
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mart [117]

Answer:

reaction B is the best one I would choose

3 0
3 years ago
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

4 0
3 years ago
How many pounds does 1.00 quart of mercury weight? its density is 13.6g/mL
Gala2k [10]
Two steps by inspection 1 qt = 0.25 gallons, 13.6 g/mL = 13.6 kg/L

0.25 gallon x 3.785411784 L/gallon x 13.6 kg/L x 1 lb/0.45359237 kg = 28.374 lb.

Hope this Helps!
5 0
3 years ago
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