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Vlad1618 [11]
3 years ago
8

What's the 7th term in the geometric sequence

Mathematics
1 answer:
Marta_Voda [28]3 years ago
4 0
a_{7} = 2 \times 5^{7 -1} = 2 \times 5^{6} = 2 \times 15,625 = 31,250
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If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
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3 years ago
To determine the amount of wrapping paper needed for a rectangular bow, Ryan finds the surface area of the box. How much wrappin
yulyashka [42]
Find the area. Multiply length by width
5 0
3 years ago
What answer do i need to put in the boxes
scoundrel [369]
Y-65=3(x-49) 3 is time 49 is crushed
5 0
3 years ago
Read 2 more answers
Assuming the lines are parallel angel 4 corresponds with angle ___
Soloha48 [4]

Answer:

∠ 2

Step-by-step explanation:

∠ 2 corresponds to ∠ 4 because each is in the same position, the upper right- hand corner, in its group of 4 angles.

6 0
3 years ago
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In the image below, ABC ~ DEF What is the length of EF and the measure of D
Gwar [14]
If triangle ABC is congruent to triangle DEF, then EF = BC = 27
This is because BC and EF are the last two letters of ABC and DEF respectively. They match up and correspond, being congruent by CPCTC

-------------------------------------------------------------------------------------------------------------

Similarly, if triangle ABC is congruent to triangle DEF, then angle D = angle A = 49 degrees

The letter D and the letter A are the first letters of DEF and ABC respectively. So they match up and are congruent by CPCTC

CPCTC = Corresponding Parts of Congruent Triangles are Congruent

-------------------------------------------------------------------------------------------------------------

So in short, the answer is choice B) 27; 49

7 0
3 years ago
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