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Licemer1 [7]
4 years ago
15

Given f(x) = –2x+5 find f'(x).

Mathematics
1 answer:
Anika [276]4 years ago
8 0

Answer: D

Step-by-step explanation:

To find the inverse function, you switch y with x and x with y. Then you solve for y.

y=-2x+5               [replace y with x and x with y]

x=-2y+5               [subtract both sides by 5]

x-5=-2y                 [divide both sides by -2]

(x-5)/-2=y

Now that we have our inverse function, we can rewrite it so that it matches the answer choice. D matches our answer choice the best.

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Quadrilateral BECK is known to be a rhombus. Two of the vertices are B(3,5) and C(7,-3).
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Answer:

a. The slope of EK is \frac{1}{2}

b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

Step-by-step explanation:

The form of the equation of a line is y = m x + b, where

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∵ The diagonal is the line that joins two opposite vertices

∵ B and C are opposite vertices in the rhombus

∵ E and K are opposite vertices in the rhombus

∴ BC and EK are the diagonals of the rhombus BECK

∵ The diagonals of the rhombus are ⊥ and bisect each other

∴ EK is ⊥ bisector to BC

→ Let us find the slope and the mid-point of BC

∵ B = (3, 5) and C = (7, -3)

∴ x1 = 3 and y1 = 5

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→ Substitute them in the rule of the slope above to find it

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∴ m = -2

∴ The slope of BC = -2

→ To find the slope of EK reciprocal the slope of BC and change its sign

∴ m⊥ = \frac{1}{2}

∴ The slope of EK = \frac{1}{2}

a. The slope of EK is \frac{1}{2}

→ Substitute the value of the slope in the form of the equation above

∵ y = \frac{1}{2} x + b

→ To find b substitute x and y in the equation by the coordinates

   of a point on the line

∵ The mid-point of BC is the mid-point of EK

∵ The mid-point of BC = (\frac{3+7}{2},\frac{5+-3}{2}) = (\frac{10}{2},\frac{2}{2}) = (5, 1)

∴ The mid-point of EK = (5, 1)

→ Substitute x by 5 and y by 2 in the equation

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→ Substitute the value of b in the equation

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b. The equation of line EK is y = \frac{1}{2} x -  \frac{3}{2}

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