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3 years ago

The box plots show the average gas mileage of cars and minivans tested by a certain company.

Mathematics

2 answers:

Wittaler [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Svetllana [295]3 years ago

6 0

Answer:

B, Josef is confused about the range and the interquartile range.

Step-by-step explanation:

You have to make the box plot using the numbers given

Find the IQR *interquartile range* and the difference between the max and the minimum numbers.

For the cars the IQR is: 6

The range for the cars is: 12

The IQR of the minivan is: 3

The range of the minivan is: 12

The ranges are the same but IQR of the cars is bigger, that's where Josef got confused.

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Find the lateral surface area of the cylinder. Round your answer to the nearest tenth.

zheka24 [161]

Answer:

The answer is "The second choice".

Step-by-step explanation:

$r=6\\\\h=13 \\\\$

Formula:

$A=2\pi rh$

$=2\times 3.14 \times 6 \times 13\\\\=2\times 3.14 \times 78\\\\=3.14 \times 156\\\\=3.14 \times 156\\\\=489.84 \approx 489.8 ft^2$

5 0

3 years ago

Please answer correctly!! You will be reported if you don't!!

serious [3.7K]

Answer:

QUESTION?

Step-by-step explanation:

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3 years ago

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Help asap please! 2/5+????=7/10 Find the missing fraction

docker41 [41]

Answer:

3/10

Step-by-step explanation:

2/5 + x = 7/10

x = 7/10 - 2/5

x = 7/10 - 4/10

x = 3/10

8 0

2 years ago

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A boat starts from a port and moves 12 miles north and then moves 5 miles east. what is the present distance of the boat from th

disa [49]

If you sketch the path of the boat, you will form a right triangle towards the port. The distance from the port to the present position is the hypotenuse since it is opposite from the right angle formed by the 12 miles north and 5 miles east movement. Since it is a right triangle, use the Pythagorean Theorem to solve the hypotenuse.

Solution:

h² = o² + a²
h² = 12² + 5²
h² = 144 + 25
h² = 169
√h² = √169
h= 13

The present distance of the boat from the port is 13 miles.

7 0

3 years ago

A new medical test provides a false positive result for hepatitis 2% of the time that is a perfectly healthy subject being teste

Oxana [17]

Given that X be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.

The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02

Part A:

The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:

 $P(X)={ ^nC_xp^x(1-p)^{n-x}} \\ \\ P(0)={ ^{30}C_0(0.02)^0(1-0.02)^{30-0}} \\ \\ =1(1)(0.98)^{30}=0.5455$


Part B:

The mean of a binomial distribution is given by

 $\mu=np \\ \\ =30(0.02) \\ \\ =0.6$

The standard deviation is given by:

 $\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{30(0.02)(1-0.02)} \\ \\ =\sqrt{30(0.02)(0.98)}=\sqrt{0.588} \\ \\ =0.7668$


Part C:

This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.

5 0

3 years ago