The area of the shaded region in the task content is; 251.2.
<h3>What is the area of the shaded region in the task content?</h3>
It follows from the task content that the area of the shaded region is;
= Area of semicircle IL - Area of semicircle JK + Area of semicircle IJ + Area of semicircle KL.
Hence, since the radius of each semicircle are as follows;
R(IL) = 12
R(IJ) = R(JK) = R(KL) = 4.
Hence, the Area of the shaded region can be evaluated as;
= (π/2)(12² - 4² + 4² +4²).
= π (144 +16)
= (3.14/2) × 160 = 251.2
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Answer:828.96m^2
Step-by-step explanation:
radius(r)=8m
L=25m
π=3.14
total surface area of cone(tsa)=πxr^2+πxrxL
Tsa=3.14x8^2+3.14x8x25
Tsa=3.14x8x8+3.14x8x25
Tsa=200.96 + 628
Tsa=828.96
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
Answer: transportation
Step-by-step explanation: