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dimaraw [331]
3 years ago
8

20,000 Leagues Under the Sea is a classic science fiction novel by French writer Jules Verne. How many kilometers are in 20,000

leagues? (Round to the nearest whole number and do not include units or commas in your answer.) Note: There are 15,840 feet in a league and 3.28 feet in a meter
Mathematics
2 answers:
vivado [14]3 years ago
5 0

Answer:

111120

Step-by-step explanation:

34kurt3 years ago
4 0

Answer:

96585

Step-by-step explanation:

15,840 x 20,000 = 316,800,000 ft

316,800,000 / 3.28 = 96,585,365.9 meters

meters to km = 96,585.3659 km or rounded = 96,585 km

remember king henry died by drinking chocolate milk for metric conversions

kilo,hecto,deca,(meter),deci,centi,milli

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Answer:

We have the matrix A=\left[\begin{array}{ccc}-4&-4&-4\\0&-8&-4\\0&8&4\end{array}\right]

To find the eigenvalues of A we need find the zeros of the polynomial characteristic p(\lambda)=det(A-\lambda I_3)

Then

p(\lambda)=det(\left[\begin{array}{ccc}-4-\lambda&-4&-4\\0&-8-\lambda&-4\\0&8&4-\lambda\end{array}\right] )\\=(-4-\lambda)det(\left[\begin{array}{cc}-8-\lambda&-4\\8&4-\lambda\end{array}\right] )\\=(-4-\lambda)((-8-\lambda)(4-\lambda)+32)\\=-\lambda^3-8\lambda^2-16\lambda

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Let's find the eigenspaces of A. For \lambda_{1}=0: E_0 = Null(A- 0I_3)=Null(A).Then, we use row operations to find the echelon form of the matrix

A=\left[\begin{array}{ccc}-4&-4&-4\\0&-8&-4\\0&8&4\end{array}\right]\rightarrow\left[\begin{array}{ccc}-4&-4&-4\\0&-8&-4\\0&0&0\end{array}\right]

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Therefore,

E_0=\{(x,y,z): (x,y,z)=(-\frac{1}{2}t,-\frac{1}{2}t,t)\}=gen((-\frac{1}{2},-\frac{1}{2},1))

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