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3 years ago

Find the perimeter of a table cloth that is forty inches square.

Mathematics

2 answers:

omeli [17]3 years ago

3 0

Answer: Either 28in or 26in

A table cloth 40 inches squared could be 1 by 40, 2 by 20, 4 by 10, 5 by 8

1 by 40 would have a perimeter of 1(2) + 40(2) = 82in

2 by 20 would have a perimeter of 2(2) + 20(2) = 44in

4 by 10 would have a perimeter of 4(2) + 10(2) = 28in

5 by 8 would have a perimeter of 5(2) + 8(2) = 26in

1 by 40, and 2 by 20 are highly unlikely table cloths so it is either 26in or 28in

lapo4ka [179]3 years ago

3 0

Answer:

8√(10)

Step-by-step explanation:

The area of a square is given by the formula

A = s²

Since the area is 40, that gives us

40 = s²

Take the square root of each side:

√(40) = √(s²)

√(4*10) = s

2√(10) = s

Since each side of a square is the same length, this makes the perimeter

2√(10)+2√(10)+2(√10)+2(√10) = 8√(10)

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3 years ago

There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit

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Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = $nCr * p^{r} * q^{n-r}$

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = $15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}$

p(x=3) = 455 * $0.4^{3} * 0.6^{12}$

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday = 1 - 0.0633 = 0.9337

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3 years ago