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alex41 [277]
3 years ago
6

Step by step how to factor: 2y^2+9y+9=0

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0
Use ac method
for ax²+bx+c=0 when a≠1


multiply a and c, let's call the product r
what 2 numbesr multiply to get r and add to get b


2y²+9y+9=0
2*9=18
wat 2 numbers multiply to get 18 and add to get 9
3 and 6
split it up to that

2y²+3y+6y+9=0
group
(2y²+3y)+(6y+9)=0
factor
y(2y+3)+3(2y+3)=0
undistribute
(y+3)(2y+3)=0
set to zero

y+3=0
y=-3

2y+3=0
2y=-3
y=-3/2


y=-3 and -3/2
it's factored form is (x+3)(2x+3)
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The answer is, 9/50
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In conclusion the answer is 9/50.
Hopefully that helped! :)
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Step-by-step explanation:

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

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