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2 years ago

WILL MARK BRANLIST!!!

Mathematics

2 answers:

nirvana33 [79]2 years ago

8 0

Hope It Helps
Brainliest pls!

miv72 [106K]2 years ago

6 0

Answer:

Step-by-step explanation:

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Linda gets paid $80 per day. Unfortunately Linda went home sick after working 1/3 of the day on Friday. At her company they don’

Ludmilka [50]

Answer:

26.67

Step-by-step explanation:

Take the total amount per day and multiply by the fraction of the day that she worked

80 *1/3 =26.66666

Rounding to the nearest cent

26.67

7 0

2 years ago

Can someone help me from one two four please

Lunna [17]

1. 15 / 1/3

When dividing, the second fraction flips over .

15* 3/1= 45/1= 45

2. 24 / 1/6

24*6= 144

4. 7/12 / 1/3

7/12*3/1

Cross out 3 and 12, divide by 3

12/3= 4

3/3= 1

7/4* 1/1. Multiply the numerator together. Multiply the denominators together.

7*1= 7

4*1= 4

7/4 or 1 3/4

Answers :

1. 45

2. 144

4. 7/4 or 1 3/4

7 0

3 years ago

Read 2 more answers

It costs you $22.25 per day to rent a car in New York City. In addition, you have to pay 16 cents for every mile you travel. How

olganol [36]

Answer: $178.13

Step-by-step explanation:

418x0.16=66.88

22.25x5=111.25

111.25+66.88=178.13

4 0

3 years ago

Which function can be used to find the number of ounces of coffee in the can based on its radius?

8090 [49]

Answer:

Step-by-step explanation:

The answer is A I hope it helped!

5 0

3 years ago

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equa

arlik [135]

Answer:

Yes. At this significance level, there is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

Step-by-step explanation:

The question is incomplete:

The significance level is 0.05.

The data is:

Brand X: 91, 100, 88, 89

Brand Y: 99, 96, 94, 99

Brand Z: 83, 88, 89, 76

We have to check if there is a significant difference between the absorbency rating of each brand.

Null hypothesis: all means are equal

$H_0:\mu_x=\mu_y=\mu_z$

Alternative hypothesis: the means are not equal

$H_a: \mu_x\neq\mu_y\neq\mu_z$

We have to apply a one-way ANOVA

We start by calculating the standard deviation for each brand:

$s_x^2=30,\,\,s_y^2=6,\,\,s_z^2=35.33$

Then, we calculate the mean standard error (MSE):

$MSE=(\sum s_i^2)/a=(30+6+35.33)/3=71.33/3=23.78$

Now, we calculate the mean square between (MSB), but we previously have to know the sample means and the mean of the sample means:

$M_x=92,\,\,M_y=97,\,\,M_z=84\\\\M=(92+97+84)/3=91$

The MSB is then:

$s^2=\dfrac{\sum(M_i-M)^2}{N-1}\\\\\\s^2=\dfrac{(92-91)^2+(97-91)^2+(84-91)^2}{3-1}\\\\\\s^2=\dfrac{1+36+49}{2}=\dfrac{86}{2}=43\\\\\\\\MSB=ns^2=4*43=172$

Now we calculate the F statistic as:

$F=MSB/MSE=172/23.78=7.23$

The degrees of freedom of the numerator are:

$dfn=a-1=3-1=2$

The degrees of freedom of the denominator are:

$dfd=N-a=3*4-3=12-3=9$

The P-value of F=7.23, dfn=2 and dfd=9 is:

$P-value=P(F>7.23)=0.01342$

As the P-value (0.013) is smaller than the significance level (0.05), the null hypothesis is rejected.

There is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

3 0

3 years ago