Answer:
The distance of ship B from the Harbor is 32.26 miles
Step-by-step explanation:
Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.
I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.
.... flip both fractions.
.... multiply both sides by 22
So the distance of ship B from the Harbor is 32.26 miles
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Add 0.1 to 0.0(54) to get 0.1(54).
Chapter : Linear equations
Lesson : Math for Junior High School
7x + 14y = 28
if want to find x and y, we must substitution value 0 to the equation x and y :
# If x = 0, then :
7x + 14y = 28
= 7(0) + 14y = 28
= 0 + 14y = 28
= 14y = 28 → y = 28/14
= y = 2
# If y = 0, then :
7x + 14y = 28
= 7x + 14(0) = 28
= 7x + 0 = 28
= 7x = 28 → x = 28 / 7
= x = 4
and that result was proven x = 4 and y = 2
Description: They didn't distribute the 3 to both x and 5, so they just had 3x+5.
actual problem:
3(x+5)=3x+15
3x+15=3x+15
subtract 3x from both sides and end up with
15=15
Correct Answer: 15=15
False because there are no parrelell lines
