The price of one bag of popcorn is $3.75
Step-by-step explanation:
Let,
x represent the cost of a bag of popcorn
y represent the cost of a drink.
According to given statement;
4x+12y=30 Eqn 1
x+6y=11.25 Eqn 2
Multplying Eqn 2 by 2
Subtracting Eqn 3 from Eqn 1
Dividing both sides by 2
4x+12y=30 and x+6y=11.25 can be used to find the price of one bag of popcorn and the price of one drink.
The price of one bag of popcorn is $3.75
Keywords: linear equation, elimination method
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Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
Answer:
50
Step-by-step explanation:
sides are = so angles are also = !
Answer:
(c) if n is large, then the sampling distribution of the sample mean can be approximated closely by a normal curve.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample mean, with a large sample size, can be approximated to a normal distribution with mean and standard deviation 
.
This is valid no matter the shape of the population.
So the correct answer is:
(c) if n is large, then the sampling distribution of the sample mean can be approximated closely by a normal curve.
B the only solution is X=9/10 therefore making it only one solution
