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2 years ago

An equation for the line that has a slope of 1/2 and passes through the point (-2,5)

Mathematics

1 answer:

Oksi-84 [34.3K]2 years ago

8 0

Answer:

$y = 1/2x + 6$

Step-by-step explanation:

Step 1: Find the equation

$(y - y_1) = m(x - x_1)$

$(y - (5)) = 1/2(x - (-2))$

$y - 5 = 1/2(x + 2)$

$y - 5 + 5 = 1/2x + 1 + 5$

$y = 1/2x + 6$

Answer: $y = 1/2x + 6$

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Answer:

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Step-by-step explanation:

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2 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

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2 years ago

Evaluate v+t when t=4x-1 and v=2x+1

Rainbow [258]

You would simply add the last two equations together. If v=2x+1 and t=4x-1, you can add them up. This would make 2x+1+4x-1. If you combine like terms, 1 and -1 cancel out and you are left with 6x. This means x can be anything.

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3 years ago

What is the shape of a dice

Nikitich [7]

The shape of a dice is a cube. A cube is a shape which is 3D. A cube has 6 squares which makes it 3D. A dice has dots on them. The dots stand for numbers. Each side has a different number. They have up to 6 dots.

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3 years ago

Read 2 more answers

Factorise fully the following: a) x² + 2x b) 2x² - 6x c) 15x - 10x³ d) 9x² + 3x³

Lostsunrise [7]

Answer:

a) $x(x+2)$