Answer:
25 ft^2
Step-by-step explanation:
In direct variation, if y varies directly with x, then the equation has the form
y = kx,
where k is the constant of proportionality. y is proportional to x.
Let's call the area y and the distance x.
Here, the area varies with the square of the distance, so the equation has the form
y = kx^2
Here, y is proportional to the square of x.
We can find the value of k by using the given information.
y = kx^2
When x = 20 ft, y = 16 ft^2.
16 = k(20^2)
k = 16/400
k = 1/25
The equation of the relation is:
y = (1/25)x^2
Now we use the equation we found to answer the question.
What is y (the area) when x (the distance) is 25 ft?
y = (1/25)x^2
y = (1/25)(25^2)
y = 25
Answer: 25 ft^2
Answer:
Ok, the domain is the set of values that we can input in a function.
In this case, we have:
y = Ix - 6I + 3.
Notice that there is no restriction here, x can actually take any value, then the domain will be the set of all real numbers.
The correct domain is x, x ∈ R
Now, if we had (for example) something like:
y = Ix - 6I < 3
Now we have a restriction in the domain because we can not have y equal or larger than 3.
To find the domain, we can break the absolute value:
Ix - 6I < 3
is equivalent to:
-3 < x - 6 < 3
now let's add 6 in each side.
-3 + 6 < x - 6 + 6 < 3 + 6
3 < x < 9
That will be the domain in that case.
Xy = 54
x + y = 7
















x + y = 7
3.5 + 6.45i + y = 7
- (3.5 + 6.45i) - (3.5 + 6.45i)
y = 3.5 - 6.45i
(x, y) = (3.5 + 6.45i, (3.5 - 6.45i)
or
x + y = 7
3.5 - 6.45i + y = 7
- (3.5 - 6.45i) - (3.5 - 6.45i)
y = 3.5 + 6.45i
(x, y) = (3.5 - 6.45i, 3.5 + 6.45i)
The two numbers that add up to 7 and can multiply to 54 is 3.5 ± 6.45i.