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natali 33 [55]
3 years ago
11

Kelsey drew a rectangle with the same area as the square. The length of Kelsey's rectangle is 8 inches. What is the perimeter in

inches of Kelsey's rectangle

Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0

Answer:  The answer is 20 inches.


Step-by-step explanation:  As given in the question and shown in the attached figure, Keyley drew the rectangle 'R' and square 'S' with equal areas.

Also, the length of Keyley's rectangle 'R' = 8 inches. Let the breadth be 'b' inches. Again, let 'l' be the length of a side of square 'S'.

Then, we must have

8\times b=\ell^2.

Now, the only possible value of b is 2, so that

\ell^2=16\\\\\Rightarrow \ell=4.

Thus, the breadth of 'R' is b = 2 inches and side of 'S' = 4 inches.

Therefore, perimeter of Keyley's rectangle 'R' is given by

p=8+2+8+2=20~\textup{inches}.

Thus, the answer is 20 inches.


aksik [14]3 years ago
5 0

Answer:

perimeter of Keyley's rectangle  is 20 inches.

Step-by-step explanation:

Given : Keyle drew the rectangle 'R' and square 'S' with equal areas.The length of Kelsey's rectangle is 8 inches.

Find:   What is the perimeter in inches of Kelsey's rectangle.

Solution:

Length of Keyley's rectangle  = 8 inches.

Let the breadth be 'b' inches. Again, let 'l' be the length of a side of square .

Area of rectangle = area of square

length * width =  length *length

8 * width = l^{2}

Now, the only possible value of b is 2, so that

Area of square ( l^{2} )= 16

Plugging the values of l^{2} = 16 in 8 * width = l^{2}

8 * width =16

Width = 2

Perimeter of rectangle = 2 ( length + width)

Perimeter = 2 ( 8 + 2 )

Perimeter = 20 inches

Therefore, perimeter of Keyley's rectangle  is 20 inches.

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