Question

Kelsey drew a rectangle with the same area as the square. The length of Kelsey's rectangle is 8 inches. What is the perimeter in inches of Kelsey's rectangle

Answer 1

Answer:  The answer is 20 inches.

Step-by-step explanation:  As given in the question and shown in the attached figure, Keyley drew the rectangle 'R' and square 'S' with equal areas.

Also, the length of Keyley's rectangle 'R' = 8 inches. Let the breadth be 'b' inches. Again, let 'l' be the length of a side of square 'S'.

Then, we must have

$8\times b=\ell^2.$

Now, the only possible value of b is 2, so that

$\ell^2=16\\\\\Rightarrow \ell=4.$

Thus, the breadth of 'R' is b = 2 inches and side of 'S' = 4 inches.

Therefore, perimeter of Keyley's rectangle 'R' is given by

$p=8+2+8+2=20~\textup{inches}.$

Thus, the answer is 20 inches.

Answer 2

Answer:

perimeter of Keyley's rectangle  is 20 inches.

Step-by-step explanation:

Given : Keyle drew the rectangle 'R' and square 'S' with equal areas.The length of Kelsey's rectangle is 8 inches.

Find:   What is the perimeter in inches of Kelsey's rectangle.

Solution:

Length of Keyley's rectangle  = 8 inches.

Let the breadth be 'b' inches. Again, let 'l' be the length of a side of square .

Area of rectangle = area of square

length * width =  length *length

8 * width = $l^{2}$

Now, the only possible value of b is 2, so that

Area of square ( $l^{2}$ )= 16

Plugging the values of $l^{2}$ = 16 in 8 * width = $l^{2}$

8 * width =16

Width = 2

Perimeter of rectangle = 2 ( length + width)

Perimeter = 2 ( 8 + 2 )

Perimeter = 20 inches

Therefore, perimeter of Keyley's rectangle  is 20 inches.