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earnstyle [38]
3 years ago
9

For questions 18-20, decide whether each transformation will result in congruent or similar figures.​

Mathematics
1 answer:
nlexa [21]3 years ago
4 0

18. The shape is only shifted to a different location and orientation but remains the same size so this is congruent.

19 and 20 are both scaled to a different size so they are both similar.

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Using the following image, solve for SR. Look at the image closely.
iren [92.7K]

Step-by-step explanation:

I assume

SR = 2x + 23

RQ = x + 21

if that is true, then the situation is completely simple :

14 = (2x + 23) + (x + 21) = 3x + 44

3x = -30

x = -10

SR = 2×-10 + 23 = -20 + 23 = 3

RQ = -10 + 21 = 11

4 0
2 years ago
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PLEASE PLEAE PLEASE!!!! HELP ME
taurus [48]

Answer:

My best answer. Hope this helps...

Step-by-step explanation:

You can see 1 full square in the triangle.

There are also 3 half squares.

The top part of the triangle also equals to 1 half square.

On the bottom right side, you have two shapes that add up to a square.

4 half squares = 2 full squares.

2 + 1 + 1 = 4

The square also has 4 squares.

8 0
3 years ago
Which equation results from adding the equations in this system?
Diano4ka-milaya [45]

Answer:

  • D. - 5x = - 10

Step-by-step explanation:

<u>Given equations:</u>

  • -8x+8y = 8
  • 3x-8y=-18

<u>Add together:</u>

  • -8x + 8y + 3x - 8y = 8 - 18
  • - 5x = - 10

Correct option is D

7 0
3 years ago
Mr. phill stopped to fill his car with gas on the way to New York. It took 1 ¼ minutes to fill a 15 liters of gas in his tank. A
KatRina [158]

Answer:

  • 4 1/6 min or 4 min 10 sec

Step-by-step explanation:

<u>Filling rate is:</u>

  • 15 ÷ 1 1/4 = 15 ÷ 5/4 = 15 × 4/5 = 12 l/min

<u>Total volume is 50 l, time required to fill is:</u>

  • 50/12 = 4 2/12 = 4 1/6 min or 4 min 10 sec
4 0
3 years ago
After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos
igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}

and we found the distance PQ and QA

; d_{PQ}=\sqrt{125}, d_{QA}=12

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0
3 years ago
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