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Sati [7]
3 years ago
6

The box plots below show the ages of college students in different math courses.

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

The correct option for this is C.) The mean and median age are more likely to be the same for the students in Math 1.

Step-by-step explanation:

i) The median age of the students is Math 1 is less than the median age of the students in Math 2.

This statement is NOT TRUE as the median age of students in Math 1 = median age of students in Math 2 = 19

ii) The mean and median age are most likely the same for both sets of data.

   This statement is NOT TRUE. The mean age of students in Math 2 should be greater than mean age of students in Math 1.

iii) The mean and median age are more likely to be the same for the students in Math 1.

  This statement is TRUE.

Anit [1.1K]3 years ago
8 0

Answer:

The mean and median age are more likely to be the same for the students in Math 1.

Step-by-step explanation:

The median age of the students for the student is Math 1 is less than the median age of the students in Math 2.

The statement is not true as the median age of students in Math 1 is equal to the median age of the students in Math 2 = 19.

Also, the mean and median age are the most likely to be the same for both sets of data.

The above statement is also not true as the mean age of students in Math 2 should be greater than the mean age of students in Math 1.

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The solution to the problem is as follows:

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</span>
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Therefore, √28 + √64 = <span>2√7. + 8 

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