Answer:
The base of the ladder is 3.2 meters far from the wall.
Step-by-step explanation:
We need to calculate the base of a right triangle. The given information is:
h: hypotenuse = length of the ladder = 6 m
b: is the base =?
θ: is the angle between the hypotenuse and the base = 58°
To find the base we can use the following trigonometric equation:


Therefore, the base of the ladder is 3.2 meters far from the wall.
I hope it helps you!
According to the secant-tangent theorem, we have the following expression:

Now, we solve for <em>x</em>.

Then, we use the quadratic formula:
![x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Where a = 1, b = 6, and c = -315.
![\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x_%7B1%2C2%7D%3D%5Cfrac%7B-6%5Cpm%5Csqrt%5B%5D%7B6%5E2-4%5Ccdot1%5Ccdot%28-315%29%7D%7D%7B2%5Ccdot1%7D%20%5C%5C%20x_%7B1%2C2%7D%3D%5Cfrac%7B-6%5Cpm%5Csqrt%5B%5D%7B36%2B1260%7D%7D%7B2%7D%3D%5Cfrac%7B-6%5Cpm%5Csqrt%5B%5D%7B1296%7D%7D%7B2%7D%20%5C%5C%20x_%7B1%2C2%7D%3D%5Cfrac%7B-6%5Cpm36%7D%7B2%7D%20%5C%5C%20x_1%3D%5Cfrac%7B-6%2B36%7D%7B2%7D%3D%5Cfrac%7B30%7D%7B2%7D%3D15%20%5C%5C%20x_2%3D%5Cfrac%7B-6-36%7D%7B2%7D%3D%5Cfrac%7B-42%7D%7B2%7D%3D-21%20%5Cend%7Bgathered%7D)
<h2>Hence, the answer is 15 because lengths can't be negative.</h2>
Answer: A .0115
Step-by-step explanation:
There are 1000 mg in a gram. So to convert to grams, you would divide by 1000
Step-by-step explanation:
Kx = u - y
Divide both sides by k
X = <u>u</u><u> </u><u>-</u><u> </u><u>y</u>
K
I think that's the answer
Hope it helps:)
Answer:
Step-by-step explanation:
4x + 1
The quotient (f/g)(x) is (f/g)(x) = ---------------
x^2 - 5
Note that x^2 means "square of x," whereas "x2" is ambiguous.