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3 years ago

Examining the figure, how many orders of magnitude larger is a person than a bacterial cell?

1 answer:

4 0

This question is repeated. I will copy the same answer provided by myself.

Well you did not show the figure, but I can show you how to do it.

Suppose the person is 6 feet tall and the bacteria cell is 1 micrometer in length.

So, put both magnitudes in the same units. I will use meter.

Person: 6 feet * 0.3048 m / foot = 1.8288 m, which in orders of magnitud is about 2 m

Bacteria cell: 1 micrometer * 1 m / 1,000,000 micrometer = 1 * 10 ^ -6 m.

Now divide: 2m / 10^ -6 m = 2,000,000

So a person is about 2 million times larger than a bacteria cell.

If the numbers in your figure are different you can use the same method to get a new result according to your figure.

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A soccer player practices kicking the ball into the goal from halfway down the soccer field, which is 45 meters away. The time i

aksik [14]

Answer:

Yes, displacement is 45 meters, time is three seconds, and the direction is toward the goal. Velocity is 15 m/s towards the goal.

Explanation:

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3 years ago

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Which forces are contact forces? which r non contact forces/

stellarik [79]

Magnetic force, i did the test

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3 years ago

Determine the heat energy needed to raise the temperature of 120 grams of ice at -5 to steam at 115°

CaHeK987 [17]

Answer:

Q = 30355.2 J

Explanation:

Given data:

Mass of ice = 120 g

Initial temperature = -5°C

Final temperature = 115°C

Energy required = ?

Solution:

Specific heat capacity of ice is = 2.108 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT = T2 -T1

ΔT = 115 - (-5°C)

ΔT = 120 °C

Q = 120 g × 2.108 j/g.°C × 120 °C

Q = 30355.2 J

5 0

4 years ago

100 POINTS FOR QUESTION

Vinil7 [7]

Answer:

do not know

Explanation:

4 0

3 years ago

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B. if 6.73 g of na2co3 is dissolved in enough water to make 250. ml of solution, what is the molar concentration of sodium carbo

BARSIC [14]

Answer:- $[Na_2CO_3]=0.254M$ , $[Na^+]=0.508 M$ , $[CO_3^2^-]=0.254M$

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL. Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

$\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})$

= $0.254MNa_2CO_3$

So, molarity of sodium carbonate solution is 0.254 M.

sodium carbonate dissociate to give the ions as:

$Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-$

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

$[Na^+]=2(0.254M)$ = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

$[CO_3^2^-]=0.254M$

5 0

4 years ago