1,3,2
The coefficient multiplied by the subscript will give you how many atoms of the element there are.
So, if we plug in 1,3,2
There will be 2 Nitrogen and 6 Hydrogen in the reactants side of the equation. To balance this on the other side, we must put a 2 in order to get 2 Nitrogen and 6 Hydrogen again.
Answer:
Yes
Explanation:
Atoms are generally classified as pure substances. A pure substance has the following properties:
- All parts are the same throughout i.e. homogeneous
- They have definite composition
- The cannot easily be broken down into simpler substances by physical means.
- Separation by physical methods is not easy.
- They have unique sets of physical properties.
Elements and compounds are generally classified as pure substances. Since atoms are the building blocks of pure substances, they can be classified as one.
1 calorie is equal to 4.184 Joules.
Answer:
c. 56
Explanation:
Convert molecules --> moles --> grams
1.2 x 1024 molecules CO * 1 mol/6.022 x 1023 molecules * 28.01 g/1 mol = 55.8153438
Rounded is 56
Let me know if you need further explanation!!
Answer:
- A) pH = 2.42
- B) pH = 12.00
Explanation:
<em>The dissolution of HCl is HCl → H⁺ + Cl⁻</em>
- To solve part A) we need to calculate the concentration of H⁺, to do that we need the moles of H⁺ and the volume.
The problem gives us V=2.5 L, and the moles can be calculated using the molecular weight of HCl, 36.46 g/mol:
= 9.60*10⁻³ mol H⁺
So the concentration of H⁺ is
[H⁺] = 9.60*10⁻³ mol / 2.5 L = 3.84 * 10⁻³ M
pH = -log [H⁺] = -log (3.84 * 10⁻³) = 2.42
- <em>The dissolution of NaOH is NaOH → Na⁺ + OH⁻</em>
- Now we calculate [OH⁻], we already know that V = 2.0 L, and a similar process is used to calculate the moles of OH⁻, keeping in mind the molecular weight of NaOH, 40 g/mol:
= 0.02 mol OH⁻
[OH⁻] = 0.02 mol / 2.0 L = 0.01
pOH = -log [OH⁻] = -log (0.01) = 2.00
With the pOH, we can calculate the pH:
pH + pOH = 14.00
pH + 2.00 = 14.00
pH = 12.00