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3 years ago

Determine the heat energy needed to raise the temperature of 120 grams of ice at -5 to steam at 115°

Chemistry

1 answer:

CaHeK987 [17]3 years ago

5 0

Answer:

Q = 30355.2 J

Explanation:

Given data:

Mass of ice = 120 g

Initial temperature = -5°C

Final temperature = 115°C

Energy required = ?

Solution:

Specific heat capacity of ice is = 2.108 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = m.c. ΔT

ΔT = T2 -T1

ΔT = 115 - (-5°C)

ΔT = 120 °C

Q = 120 g × 2.108 j/g.°C × 120 °C

Q = 30355.2 J

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3 years ago

The density of benzene is 0.879g/mL. The volume (with 1 decimal) of 131.9g sample of benzene is how many mL?

timurjin [86]

Answer:

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Explanation:

Step 1: Given data

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Step 2: Calculate the volume of the sample of benzene

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3 years ago

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Liono4ka [1.6K]

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2 years ago

When potassium metal is placed in water a large amount of energy is released as potassium hydroxide and hydrogen gas are produce

Ann [662]

Explanation:

$2K(s)+2H_2O\rightarrow 2KOH(aq)+H_2(g)$

The given reaction is redox reaction but not combustion reaction.

Redox reaction : It is a chemical reaction in which oxidation and reduction occurs simultaneously.Oxidation is gaining of electrons and reduction is loosing of electrons.

$K\rightarrow K^++e^-$ oxidation

$2H^++2e^-\rightarrow H_2$ reduction

Potassium when reacts with water ,gives potassium ion in aqueous medium and combines with hydroxide ion present in water to form potassium hydroxide where as $H^+$ ions of water by gaining electrons (from potassium in water) gives hydrogen gas.

Hence , yes it is a redox reaction

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Here in given reaction no oxygen molecule is appearing on reactant side.

Hence not a combustion reaction.

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2 years ago