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Juli2301 [7.4K]
2 years ago
9

Antique paintings will deteriorate more rapidly in a humid environment. Art museums will combat this by placing a desiccant into

the room to lower the moisture in the air. The chemicals used for this are strongly attracted to the water in the air, some so much that they actually pull enough water out of the air to form a solution. These are known as deliquescents. One common deliquescent is iron(III) chloride. A curator places a dish with 8.65x1023 formula units of iron(III) chloride into a museum storage room. This dish contains ___ grams of iron(III) chloride.
Chemistry
1 answer:
stira [4]2 years ago
3 0

233.1g

Explanation:

Given:

Formula units of FeCl₃ = 8.65 x 10²³ formula units

Unknown:

Mass of the FeCl₃ = ?

Solution:

The formula unit is the same as the amount of subatomic particles in an atom.

  1 mole of a substance = 6.02 x 10²³ formula units

 For  8.65 x 10²³ formula units; the number of moles;

  Number of moles = \frac{8.65 x 10 ^{23} }{6.02 x 10^{23} } = 1.44moles

Now to find the mass of  FeCl₃;

   Mass of  FeCl₃ = 1.44 x 162.2 = 233.1g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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6 0
3 years ago
If .758 moles of gas occupy a volume of 80.6L, how many moles will occupy a volume of 270.9L?
egoroff_w [7]

Answer:

n₂ = 2.55 mol

Explanation:

Given data:

Initial number of moles = 0.758 mol

Initial volume = 80.6 L

Final volume = 270.9 L

Final number of moles = ?

Solution:

Formula:

V₁/n₁ = V₂/n₂

V₁ = Initial volume

n₁ = initial number of moles

V₂ = Final volume

n₂ =  Final number of moles

now we will put the values in formula.

V₁/n₁ = V₂/n₂

80.6 L / 0.758 mol = 270.9 L/ n₂

n₂ = 270.9 L× 0.758 mol / 80.6 L

n₂ =  205.34 L.mol /80.6 L

n₂ = 2.55 mol

4 0
2 years ago
How many grams of aluminum chloride are needed to react completely with 1.084g lithium sulfide?
Oksi-84 [34.3K]
Molar mass :

Li₂S = <span>45.947 g/mol

AlCl</span>₃ = <span>133.34 g/mol

</span><span>3 Li</span>₂<span>S + 2 AlCl</span>₃<span> = 6 LiCl + Al</span>₂S₃

3 * 45.947 g Li₂S ----------> 2 * <span>133.34 g AlCl</span>₃
1.084 g Li₂S ----------------> ?

Mass Li₂S = 1.084 * 2 * 133.34 / 3 * 45.947

Mass Li₂S = 289.08112 / 137.841

Mass Li₂S = 2.0972 g 

hope this helps!

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3 years ago
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