Question

Find an equation for the plane containing the point (1, 2, 3) and parallel to the plane x 2y 3z

Answer 1

Answer:

Step-by-step explanation:

Heres the full question and solution:

Find an equation for the plane containing the point (1,2,3) and parallel to the plane x+2y+3z=5.

solution

Any plane parallel to $x+2y+3z=5$ is  $x+2y+3z=d$

since the plane is passing through $(1,2,3)$

we substitute point in equation

$1+2\times 2+3\times 3=d\\d=14 \\x+2y+3z=14$

equation of the line is $x+2y+3z=14$