Data:
15 16 14 15 19 17
n=6 points
sum is 96
mean is 96/6 = 16
Now we look at the absolute deviations, each of which is the absolute value of a score minus the mean, basically the distance of the score to the mean .
Scores 15 16 14 15 19 17
AbsDev 1 0 2 1 3 1
The sum of the absolute deviations is 8 and there are six of them so the
Mean Absolute Deviation = 8/6 = 4/3
Answer: 2. 8/6
<h3>Corresponding angles =
angle 1 and angle 5</h3>
They are on the same side of the transversal cut (both to the left of the transversal) and they are both above the two black lines. It might help to make those two black lines to be parallel, though this is optional.
Other pairs of corresponding angles could be:
- angle 2 and angle 6
- angle 3 and angle 7
- angle 4 and angle 8
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<h3>Alternate interior angles = angle 3 and angle 5</h3>
They are between the black lines, so they are interior angles. They are on alternate sides of the blue transversal, making them alternate interior angles.
The other pair of alternate interior angles is angle 4 and angle 6.
=======================================================
<h3>Alternate exterior angles = angle 1 and angle 7</h3>
Similar to alternate interior angles, but now we're outside the black lines. The other pair of alternate exterior angles is angle 2 and angle 8
=======================================================
<h3>Same-side interior angles = angle 3 and angle 6</h3>
The other pair of same-side interior angles is angle 4 and angle 5. They are interior angles, and they are on the same side of the transversal.
Answer:
1:05 p.m
Step-by-step explanation:
they took 35 minutes...... and they arrived at 1:40 p.m so 40-35= 5 = 1:05 p.m :)
Answer:
f(-7)=0.
f(2)=-9/5.
f(3) doesn't exist because 3 isn't in the domain of the function.
Step-by-step explanation:
is the given function.
We are asked to find:
.
f(-7) means to replace x in the expression called f with -7:
Evaluate 
at 
So f(-7)=0.
f(2) means to replace x in the expression called f with 2:
Evaluate at 
So f(2)=-9/5
f(3) means to replace x in the expression called f with 3:
Evaluate at 
Division by 0 is not allowed so 3 is not in the domain of our function.
