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3 years ago

What angle relationships are created when parallel lines are intersected by a transversal?

Mathematics

1 answer:

natka813 [3]3 years ago

7 0

Answered by Mimiwhatsup: If two parallel lines are cut by a third line, the third line is called the transversal.

Relationships:

(1) Corresponding angles

(2) Vertically Opposite angles

(3) Alternate interior angles

(4) Alternate exterior angles

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Asap plz What is the reciprocal of 2 3/8? 19/8 16/3 8/19 3/16

Zepler [3.9K]

I think it is 19/8 or 8/19 I am not sure

6 0

2 years ago

The ratio of Sam's money to Buffy's is 1.2. If Sam has $3, how much money does Buffy have? Show your work please

Bad White [126]

If the ratio is 1:2,

sam has three dollars.
buffy has six dollars.

we know this because the ratio is 1;2, so we can multiply sam’s amount by two, because buffy’s amount is twice sam’s amount.

ANSWER: buffy has 6 dollars!!

if you need the new ratio: 3:6

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2 years ago

What are the values?

zavuch27 [327]

The average of a set of numbers

Step-by-step explanation:

An Example: 4×3 gives you the value of 12.

6 0

3 years ago

Read 2 more answers

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

What triangle pairs can be mapped to each other using a single tranlation

shepuryov [24]

Answer: I think Figure 4 is the correct one

Step-by-step explanation:

It is not possible to map the triangle MNP and CDE together using just a single translation in Figure 3. With Figure 4, we can use a translation to map the triangle MNP and the triangle CDE. Accordingly, in the diagram, the triangle MNP and the triangle CDE can be translated to each other.

8 0

2 years ago