Question

Please help picture is there

Answer 1

Answer:

B

Step-by-step explanation:

Using the rule of radicals/ exponents

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

$a^{\frac{m}{n} }$ ⇔ $\sqrt[n]{a^{m} }$

Given

$\sqrt[3]{x^5 y}$

= $\sqrt[3]{x^5}$ × $\sqrt[3]{y}$

= $x^{\frac{5}{3} }$ $y^{\frac{1}{3} }$ → B