An integer is a whole number.
1) if Isaac is on the 4th floor and goes up 7, that is 4 + 7= 11. So he is on the 11th floor.
2) the integer representing the floor he is starting on is 4 because that is the whole number associated with "4th."
3) the integer representing how many floors he will rise is 7.
4) the elevator will stop at 11.
Hope this helps! :)
Answer:
6) y = x^(5/3)
7) B
8) C
10) A
Step-by-step explanation:
6) The fifth root is the same as raising to the 1/5 power, so we can write this in exponent form as:
f(x) = (x^(1/5))³
f(x) = x^(3/5)
To find the inverse, switch x and y and solve for y.
x = y^(3/5)
y = x^(5/3)
7) f(x) = 2√(x − 4) + 8
Switch the x and y and solve for y:
x = 2√(y − 4) + 8
x − 8 = 2√(y − 4)
(x − 8) / 2 = √(y − 4)
(x − 8)² / 4 = y − 4
(x² − 16x + 64) / 4 = y − 4
¼x² − 4x + 16 = y − 4
y = ¼x² − 4x + 20
8) Find the inverse:
x = 5√(y + 3) − 2
x + 2 = 5√(y + 3)
(x + 2) / 5 = √(y + 3)
(x + 2)² / 25 = y + 3
y = -3 + (x + 2)² / 25
The inverse function is an upwards parabola with a vertex at (-2, -3). The best fit is C.
desmos.com/calculator/fbabg5wc8b
10) √(4x − 31) = x − 7
Square both sides:
4x − 31 = (x − 7)²
4x − 31 = x² − 14x + 49
Combine like terms:
0 = x² − 18x + 80
Factor:
0 = (x − 8) (x − 10)
x = 8 or 10
Check for extraneous solutions.
√(4×8 − 31) = 8 − 7
1 = 1
√(4×10 − 31) = 10 − 7
3 = 3
x = 8 and x = 10 are both solutions.
Answer:
- 3.6 pounds of granola and 5.4 pounds of nuts
Step-by-step explanation:
Let the required granola be x pounds, then amount of nuts is 9 - x.
<u>The price of the mixture is as below equation:</u>
- 6.5x + 9(9 - x) = 8*9
- 6.5x + 81 - 9x = 72
- 81 - 2.5x = 72
- 2.5x = 81 - 72
- 2.5x = 9
- x = 9/2.5
- x = 3.6
<u>Find the amount of nuts:</u>
Answer:
480
Step-by-step explanation:
8x4=32
8x8=64
32x4=128
32x8=256
256+128+64+32=480
Answer:
we know that
The volume of the prism is equal to
V=L*W*H
where
L is the length side of the base of the prism
W is the width side of the base of the prism
H is the height of the prism
In this problem we have
L=\frac{d-2}{3d-9}=\frac{d-2}{3(d-3)}
W=\frac{4}{d-4}
H=\frac{2d-6}{2d-4}=\frac{2(d-3)}{2(d-2)}=\frac{(d-3)}{(d-2)}
Substitute the values in the formula
V=\frac{d-2}{3(d-3)}*\frac{4}{d-4}*\frac{(d-3)}{(d-2)}=\frac{4}{3(d-4)}=\frac{4}{3d-12}
therefore
the answer is the option
4/3d-12
Step-by-step explanation:
