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irina [24]
3 years ago
12

A web page design firm has two designs for an online hardware store. To determine which is the more effective​ design, the firm

uses one page from 1 : 00 PM until 6 : 00 PM and a second page from 6 : 00 PM until 11 : 00 PM. For each​ visit, the firm records the visitor's rating on the layout and the number of items viewed. Complete parts​ (a) through​ (c) below. ​(a) What is the explanatory variable in this​ study? Is it qualitative or​ quantitative? A. The explanatory variable is the number of items viewed. This explanatory variable is quantitative. B. The explanatory variable is the web page design. The explanatory variable is qualitative. C. The explanatory variable is the time of day. This explanatory variable is qualitative.
Mathematics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

A. The explanatory variable is the number of items viewed. This explanatory variable is quantitative.

Step-by-step explanation:

The variable that we can change is called the Explanatory Variable.

The Response variable depends upon the explanatory variable, as we change the value of the explanatory variable the value of the response variable is also get changed.

When the data is in the form of numeric, it is called quantitative.

When the data is not in the numeric form, it is called qualitative.

Here, we have to determine which web page design is better and it depends on the number of the item viewed by a visitor to that site.

Thus, the Explanatory variable is the "number of items viewed".

and the number of items viewed is numeric data, so it is quantitative.

Hence, option (A) is correct.

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Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

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3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

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Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

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Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

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The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

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The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

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Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

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