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3 years ago

What is the length of the equilateral triangle below?

Mathematics

1 answer:

kykrilka [37]3 years ago

4 0

Answer:

C. 5√3

Step-by-step explanation:

To figure this out, we need to apply the Pythagorean Theorem, a² + b² = c², where c is the "HYPOTENUSE". In this case, c is already found for us [10], so the operation we use whenever the hypotenuse is defined is deduction, or subtraction. Apply the Pythagorean Theorem: a² + 25 = 100; 75 = a². Now, to find a, we need to find two numbers that multiply to 75, where one of them is a PERFECT SQUARE, and in this case, they are 3 and 25. Since the square root of 25 is 5 [in this case, NO NON-NEGATIVE root], that gets moved to the outside of the radical, and 3 [NON-PERFECT SQUARE] stays wrapped under the radical, ending up with 5√3. You understand?

I am joyous to assist you anytime.

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tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF( $2^{4}$ ) or GF(24). i believe the question should rather be in this form;

multiplication in GF( $2^{4}$ ): Compute A(x)B(x) mod P(x) = $x^{4}$ + $x$ +1, where A(x)= $x^{2}$ +1, and B(x)= $x^{3} + x+1$ .

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)= $(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1 ) = (x^{5} +x^{3}+x^{2} ) + (x^{3}+x+1 ) mod (x^{4} + x+1 )$

= $x^{5}+2x^{3} +x^{2} + x + 1 mod(x^{4}+x+1 )$

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please note that the division by the modulus above we used

$\frac{x^{5}+2x^{3}+x^{2} +1 }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}$

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