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3 years ago

9

Trapezoid ABCD below is to be translated to

1 answer:

Anarel [89]3 years ago

6 0

Answer:

17x+13y

Step-by-step explanation:

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Which of the following could be the graph of y = xn where n is even?

MrRissso [65]

The answer is C because is n is positive and even it will only open up.

3 0

3 years ago

Read 2 more answers

Please help me with these I'm lost

Inessa [10]

Y = (2/3)x + 6
3y - 5x = 9

find an expression for y from the second equation:-
y = (5/3)x + 3
Now substitute this for y in the first equation:-
(5/3) x + 3 = (2/3)x + 6 Now solve for x:-
(5/3)x - (2/3)x = 6 - 3
x = 3
Now plug x = 3 into the second equation to find the value of y:_
3y - 5(3) =9
3y = 15+9 = 24
y = 8
So the solution is x = 3, y = 8

written as a set this is {3,8}.

3 0

3 years ago

standing on the street, the top of a building has an angle of elevation of 20 degrees. You walk 300 feet directly toward the bui

densk [106]

Answer:

The value of height of the building h = 509.2 feet

Step-by-step explanation:

From the Δ A B C

$\tan 25 = \frac{h}{y}$

⇒ h = y $\tan 25$ ° ------- (1)

From Δ A B D

$\tan 20 = \frac{h}{y + 300}$

⇒ h = ( y + 300 ) $\tan20$ ° ------- (2)

Equation 1 = Equation 2

⇒ y $\tan 25$ ° = ( y + 300 ) $\tan20$ °

⇒ 0.46 y = 0.36 y + 109.2

⇒ 0.1 y = 109.2

⇒ y = 1092 feet

Put this value of y in equation ( 1 ) we get,

⇒ h = 1092 × tan 25°

⇒ h = 509.2 feet

This is the value of height of the building.

8 0

3 years ago

What is 0.6 divided by 12.9

Digiron [165]

12.9/ .6= is 21.5 hope this is what you need!!:)

4 0

3 years ago

A point moves along the curve y = √ x in such a way that the y-component of the position of the point is increasing at a rate of

Eduardwww [97]

Answer:

The value of x component changes at a rate of $\frac{dx}{dt}=4\sqrt{x}$ units per second

Step-by-step explanation:

We are given that $y=x^{\frac{1}{2}}$

Differentiating on both sides with respect to time we get

$\frac{dy}{dt}=\frac{d\sqrt{x}}{dt}\\\\\frac{dy}{dt}=\frac{1}{2}x^{\frac{-1}{2}}(\frac{dx}{dt})\\\\\frac{dy}{dt}=\frac{1}{2\sqrt{x}}\frac{dx}{dt}$

It is given that $\frac{dy}{dt}=2units/sec$

Solving for $\frac{dx}{dt}$ we get

$\frac{dx}{dt}=\frac{dy}{dt}\times 2\sqrt{x}\\\\\frac{dx}{dt}=4\sqrt{x}$

5 0

3 years ago