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Gwar [14]
2 years ago
8

A fair die is rolled once. Let A be the event of rolling an even number, and let B be the event of rolling a number greater than

3. Find A ∩ B
Mathematics
1 answer:
IRISSAK [1]2 years ago
3 0

Answer:

A ∩ B = {4, 6}

Step-by-step explanation:

A die had 6 faces

S = {1, 2, 3, 4, 5, 6}

If A  be the event of rolling an even number, then;

A = {2, 4, 6}

If B be the event of rolling a number greater than 3, then;

B = {4, 5, 6}

A ∩ B are the values that are common to both sets

A ∩ B = {4, 6}

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Need help again. Please explain your answer.
Elis [28]

4y + 3 ≤ y + 6

4y + 3 - 3 ≤ y + 6 - 3

4y ≤ y + 3

4y - y ≤ y - y + 3

3y ≤ 3

3y/3 ≤ 3/3

y ≤ 1

So any value of y less than or equal to 1 (so 1 is included in the solution set) satisfies the inequality. C is the correct answer.

5 0
3 years ago
Find an equation in standard form for the ellipse that satisfies the given conditions. Major axis length 10 on y-axis minor axis
Helen [10]
The answe might be e= 10\16
3 0
3 years ago
Please help right away!!!
ira [324]
It depends on your goals.

typically it's B but it could be D
3 0
3 years ago
Read 2 more answers
Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer
Andrews [41]

Answer:

f(x) = \frac{24}{25} * \frac{5}{6}^x

Step-by-step explanation:

Given

(x_1,y_1) = (2,\frac{2}{3})

(x_2,y_2) = (3,\frac{5}{9})

Required

Write the equation of the function f(x) = ab^x

Express the function as:

y = ab^x

In: (x_1,y_1) = (2,\frac{2}{3})

y = ab^x

\frac{2}{3} = a * b^2 --- (1)

In (x_2,y_2) = (3,\frac{5}{9})

y = ab^x

\frac{5}{9} = a * b^3 --- (2)

Divide (2) by (1)

\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}

\frac{5}{9}/\frac{2}{3} = b

\frac{5}{9}*\frac{3}{2} = b

\frac{5}{3}*\frac{1}{2} = b

\frac{5}{6} = b

b = \frac{5}{6}

Substitute 5/6 for b in (1)

\frac{2}{3} = a * b^2

\frac{2}{3} = a * \frac{5}{6}^2

\frac{2}{3} = a * \frac{25}{36}

a = \frac{2}{3} * \frac{36}{25}

a = \frac{2}{1} * \frac{12}{25}

a = \frac{24}{25}

The function: f(x) = ab^x

f(x) = \frac{24}{25} * \frac{5}{6}^x

7 0
3 years ago
A 99% confidence interval for the mean μ of a population is computed from a random sample and found to be 6 ± 3. We may conclude
valentina_108 [34]

Answer:

A. there is a 99% probability that μ is between 3 and 9.

Step-by-step explanation:

From a random sample, we build a confidence interval, with a confidence level of x%.

The interpretation is that we are x% sure that the interval contains the true mean of the population.

In this problem:

99% confidence interval.

6 ± 3.

So between 6-3 = 3 and 6 + 3 = 9.

So we are 99% sure that the true population mean is between 3 and 9.

So the correct answer is:

A. there is a 99% probability that μ is between 3 and 9.

4 0
3 years ago
Read 2 more answers
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