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Rainbow [258]
3 years ago
9

You have just completed assaying the change in absorbance for an enzyme. The initial absorbance was 0.022; the absorbance after

5 minutes was 0.444. Calculate the rate of enzyme activity for this sample (as the increase in A per 10 minutes). Show your work. HTML EditorKeyboard Shortcuts
Biology
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

The Rate of Enzyme activity for this sample after 10 minutes will be -3.028

Explanation:

  k = \frac{1}{t}\times ln(C-C0)

Where,     t= time , C= final concentration , C₀= initial concentration

        k = \frac{1}{5}\times ln (0.44-0.22) per minute

           = \frac{1}{5}\times ln (0.22)  per min

           = \frac{1}{5}\times (-1.514) per min

k   = -0.3028 per minute

k in A per minute is = -0.3028

k in A per 10 minutes will be = 10× (-0.3028)

                                                = - 3.028

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A organ is made up of various types of tissues. They can be divided into two categories, main tissue and sporadic tissue. Main tissue or parenchyma is unique to that organ and defines the function of the organ. For example: Cortex and medulla together form the main functional tissue in kidney. Similarly, myocardium is the main tissue of the heart. Sporadic tissue has blood vessels, nerves and connective tissues.

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</span>
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