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alukav5142 [94]
4 years ago
15

10 red peppers for $5.50

Mathematics
2 answers:
Gwar [14]4 years ago
3 0

Answer:1.50

Step-by-step explanation:

EleoNora [17]4 years ago
3 0

Answer:

Step-by-step explanation:

10 red peppers = 5.50

1 red pepper = 10 ÷ 5.50 = 1.81

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Write the equation of a hyperbola with vertices at (-4, 0) and (4, 0) and co-vertices (0, 5) and (0, -5).
sukhopar [10]

Answer:

The answer to your question is  \frac{x^{2}}{16} - \frac{y^{2} }{25} = 1

Step-by-step explanation:

Data

(-4, 0)   (4, 0)

(0, 5)    (0, -5)

Plot the point to determine if it is a horizontal or vertical hyperbola

It is a horizontal hyperbola because the vertices are in a horizontal line. The center is (0, 0).

a = 4

b = 5

Formula

              \frac{x^{2} }{a^{2}} - \frac{y^{2}}{b^{2}} = 1

Substitution

             \frac{x^{2}}{4^{2}} - \frac{y^{2}}{5^{2}} = 1

Equation

            \frac{x^{2}}{16} - \frac{y^{2}}{25} = 1

3 0
3 years ago
Use the Distributive Property to rewrite the expression= 7( 11a - 6c )
Olenka [21]
The problem rewritten is 77a-42c
8 0
3 years ago
Read 2 more answers
In a math class of 40 students, there are 21 female students. Which of the following does NOT represent a ratio of the number of
babymother [125]

Answer:

Everything except 21/40. That is your ratio. The denominator always

6 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
25. The width of a rectangle is (x+1) and the length is (X-6). What is the length and width of the rectangle if the area is
Elis [28]

Answer:

x=−4 or x=9

Step-by-step explanation:

1- As we know the formula for Area of rectangle = length x width

2- Multiply given width = (x+1) with length = (x-6)

3-Equation will be (x+1)(x-6) = 30

4- Solving x^2−5 x−6  = 30

5- x^2−5 x -36 = 0

6-Factor left side of equation.

(x+4)(x−9)=0

Set factors equal to 0.

x+4=0 or x−9=0

6 0
3 years ago
Read 2 more answers
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