A= 1.142 m/hr
Width of beach at 8 p.m. = 36 m
Width of beach at 3 a.m. = (36-8) m =28 m
Average change in width(A) = change in width (Width of beach at 8 p.m.-Width of beach at 3 a.m.0/ time in hours
A= ( 36-28)/ 7
A= 8/7 m/hr
A = 1.142 m /hr
You want to take 837 out of 36.
you can get 837 out of 3 0 times so you tack on the 6(0)
you get 837 out of 36 0 times so you tack on a zero(00)
Because you are adding a 0, you are now creating a decimal
you get 837 out of 360 0 times so you tack on a 0 (00.0)
You get 837 out of 3600 4 times so you put the 4 after the 0s (00.04)
Now you multiply 4 and 837 to get 3,348 and take that away from 3600 to get 252
Not you tack on a 0.
You get 837 out of 2520 3 times so you tack the 3 on behind the 4. (0.043)
Because of significant digits, your answer is 0.043
There are four quantum numbers: n, l, ml and ms. When the orbital is 4d, the 4 is corresponding to n. Thus, n=4. Then, the d corresponds to l = 2. Now, to find the value for ml, take the values of -l to +l. Therefore,
<em>ml = -2, -1, 0, 1, 2</em>
<em>Then,ms could only be either +1 or -1.</em>
Answer: use a slope calculator
-1/6
Step-by-step explanation:
Answer:
342
Step-by-step explanation:
x=5
72+72+18(5)+9+18 (5)+9=342
