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3 years ago

15

There are 30 bicycles and 10 cars parked in the parking lot. Each bicycle had two wheels and each car had four wheels. How many

wheels are there in total?

2 answers:

liq [111]3 years ago

7 0

100 wheels is your answer!

DaniilM [7]3 years ago

3 0

The answer it will be about is that for the bicycles will be 60 nd for the cars it would be 40. Hope this will help u out.

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Using this formula l=A 1/2 what is the length of one side of a square with an area of 1,936 square kilometers? (A is the area of

Vera_Pavlovna [14]

<u>c.)44 kilometers</u>

Answer:

Solution given:

let

length =L

and

Area =A

Now

we have

Area [A]=1936 square kilometers

now

As we know that

Area of square :length *length

A=l*l

A=l²

Substituting value of A

1936=l²

doing square root on both side

$\sqrt{1936}=\sqrt{l²}$

we get

l= $\sqrt{2*2*2*2*11*11}$

l=2*2*11

l=44 kilometers

So

<u>the length of one side of a </u><u>square</u><u> </u><u>is</u><u> </u><u>4</u><u>4</u><u> </u><u>kilometers</u><u>.</u><u />

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3 years ago

Please help, I’ll mark you as brainliest!!!!!

kolezko [41]

Answer:10

Step-by-step explanation:

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3 years ago

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What is the volume of a rectangular prism with a length of 2x, a width of x−2, and a height of x + 2?

bagirrra123 [75]

$\text{Volume of rectangular prism} = \text{Length} \times \text{Width} \times \text{Height}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=2x(x-2)(x+2)\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=2x(x^2 -4)\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=2x^3-8x~~ \text{Units}^3$

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2 years ago

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NEED HELP! WILL MARK BRAINLIEST

ICE Princess25 [194]

Answer:

im pretty sure its 27.

Step-by-step explanation:

if g(x) = 20 then the new problem is 20=x-7

20=x-7 . add 7 to both sides

+7=+7 . +7 cancels out the -7

27=x . <<<answer

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3 years ago

The height of a triangle is 3cm less than twice the base. The area is 10cm2

Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

This is a solve the system question. Call H the height of the triangle and B the base. The question tells us:

$H=2B-3$

and

$\frac{B \times H}{2}=10$

Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

$\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4$

In this question, we take B=4. You can't have a negative side length so the other answer is eliminated. Now sub the value for B into either of the original equations. I'll use the first, again because H is already isolated:

$H=2(4)-3\\H=8-3\\H=5$

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3 years ago