If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?
2 answers:
Answer:
The answer is


Step-by-step explanation:
we know that


In this problem we have


so
The angle
belong to the third or fourth quadrant
The value of
is negative
Step 1
Find the value of 
Remember

we have

substitute



------> remember that the value is negative
Step 2
Find the value of 

we have


substitute


For the answer to the question above, <span>If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? </span>
<span>If 3 pi over 2 < Θ < 2π Then the signs of sinx and tanx are both negative. </span>
<span>cos(x) = sqrt(2)/2. So sin(x) = -sqrt(2)/2 and tan(x) = -1. </span>
<span>sin Θ = square root 2 over 2; tan Θ = −1 </span>
<span>sin Θ = negative square root 2 over 2; tan Θ = 1 </span>
<span>sin Θ = square root 2 over 2; tan Θ = negative square root 2 </span>
<span>sin Θ = negative square root 2 over 2; tan Θ = −1</span>
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