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Contact [7]
4 years ago
15

How much acceleration does a 10 kg object have if pushed by a 75 N force?

Chemistry
1 answer:
kramer4 years ago
3 0
  • <em>Answer:</em>

<em>a = 7.5 m/s²</em>

  • <em>Explanation:</em>

<em>Hi there !</em>

<u><em>Newton's second law </em></u>

<em>F = m×a => a = F/m </em>

<em>1 N = 1kg·m/s²</em>

<em>a = (75kg.m/s²)/10kg</em>

<em>= 7.5 m/s²</em>

<em>Good luck !</em>

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What are examples of actinides
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Answer:

Neptunium, Protactinium, plutonium and more

Explanation:

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3 years ago
If you produced 76.10 grams of potassium chloride in the reaction how many grams of potassium were required?
11111nata11111 [884]

Answer:39.8375

Explanation:

The mole for the equation is 1:1

Then the molar mass of KCl is 74.5g

Molar mass of k is 39

74.5g of KCl gives 39g of k

76.10g of KCl gives xg of k

X= 76.10×39/74.5

X= 2967.9/7

X= 39.8375

6 0
3 years ago
Suppose we want to charge a flask with 1.6 g of sugar. We put the empty flask on a balance and it is determined to weigh 330 g.
RSB [31]

Answer:

total weight to expect = 331.60 grams

Explanation:

The flask wanted to be charged with 1.6 grams of sugar. The empty flask was weighed on a balance and it was determined to weigh 330 grams . The weight we would expect when we add the sugar can be computed as follows:

weight of the empty flask = 330 grams

weight of the sugar = 1.6 grams

The weight of the flask after adding the sugar will be the sum of the weight of the sugar and the empty falsk

Therefore,

Total weight to expect = 330 grams + 1.6 grams

total weight to expect = 331.60 grams

5 0
3 years ago
Read 2 more answers
Match the acid base pairs by arranging the acid name with the conjugate base formula.
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3 years ago
What is the mass, in grams, of 1.50 mol of iron (III) sulfate? Express your answer using three significant figures. mm = nothing
Paul [167]

<u>Answer:</u>

<u>For A:</u> The mass of iron (III) sulfate is 600. g

<u>For B:</u> The moles of ammonium carbonate is 0.07216 moles

<u>For C:</u> The mass of given number of molecules of aspirin is 0.359 grams.

<u>For D:</u> The molar mass of diazepam is 284.7 g/mol

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For A:</u>

We are given:

Number of moles of iron (III) sulfate = 1.50 mol

Molar mass of iron (III) sulfate = 399.9 g/mol

Putting values in equation 1, we get:

1.50mol=\frac{\text{Mass of iron (III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron (III) sulfate}=(1.50mol\times 399.9g/mol)=600.g

Hence, the mass of iron (III) sulfate is 600. g

  • <u>For B:</u>

We are given:

Mass of ammonium carbonate = 6.935 g

Molar mass of ammonium carbonate = 96.1 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonium carbonate}=\frac{6.935g}{96.1g/mol}=0.07216mol

Hence, the moles of ammonium carbonate is 0.07216 moles

  • <u>For C:</u>

We are given:

Number of aspirin molecules = 1.20\times 10^{21}

Mass of 1 mole of aspirin = 180.16 g/mol

According to mole concept:

6.022\times 10^{23} number of molecules occupies 1 mole

So, 6.022\times 10^{23} number of molecules of aspirin has a mass of 180.16 grams

Thus, 1.20\times 10^{21} number of molecules of aspirin will have a mass of \frac{180.16g}{6.022\times 10^{23}}\times 1.20\times 10^{21}=0.359g

Hence, the mass of given number of molecules of aspirin is 0.359 grams.

  • <u>For D:</u>

We are given:

Moles of diazepam = 0.05570 mol

Given mass of diazepam = 15.86 g

Putting values in equation 1, we get:

0.05570mol=\frac{15.86g}{\text{Molar mass of diazepam}}\\\\\text{Molar mass of diazepam}=\frac{15.86g}{0.05570mol}=284.7g/mol

Hence, the molar mass of diazepam is 284.7 g/mol

6 0
3 years ago
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