Question

A chemist prepares a solution of barium chlorate BaClO32 by measuring out 33.0 umol of barium chlorate into a 500.0 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /molL of the chemist's barium chlorate solution. Be sure your answer has the correct number of significant digits.

Answer 1

Answer:

6.6 x 10⁻⁵ mol/L

Explanation:

First, we have to convert the moles from μmol to mol:

moles of solute= 33.0 μmol x (1 x 10⁶ mol)/1 μmol = 3.3 x 10⁻⁵ mol

Then, we convert the volume from mL to L:

volume = 500.0 mL x 1 L/1000 mL = 0.5 L

Finally, we calculate the concentration of the solution in mol/L by dividing the moles into the volume in liters, as follows:

mol/L = moles of solute/volume = 3.3 x 10⁻⁵ mol/(0.5 L) = 6.6 x 10⁻⁵ mol/L