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Eduardwww [97]
3 years ago
9

A container is filled with hydrogen gas. It has a volume of 4 liters and a pressure of 2 atm. If the pressure of the container i

s increased to 6 atm without removing any of the gas or changing the temperature, what will the new volume be
Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
4 0

Answer:

1.33 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

<em>(P₁V₁) = (P₂V₂)</em>

<em></em>

Knowing that:

V₁  =  4.0 L, P₁ = 2.0 atm,

V₂  =  ??? L, P₂ = 6.0 atm.

  • Applying in the above equation

(P ₁V₁) = (P₂V₂)

<em>∴ V₂ = P ₁V₁/P₂</em> = (2.0 atm)(4.0 L)/(6.0 atm) =<em> 1.33 L.</em>

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3 years ago
To balance a chemical equation it may be necessary to adjust the
Mars2501 [29]

Answer:

  • <em>To balance a chemical equation it may be necessary to adjust the </em><u>coefficients.</u>

Explanation:

The <em>coefficients</em> of a <em>chemical equation</em> are the numbers that you put in front of each reactant and product. They are used to balance the equation and comply with the law of mass conservation.

By adjusting the coefficients you obtain the relative amounts (moles) of each product and reactant, i.e. the mole ratios.

Here an example.

The first information is what is called a word equation. E.g. nitrogen and hydrogen react to form ammonia:

  • Word equation: hydrogen + nitrogen → ammonia

  • Skeleton equation: H₂ + N₂ → NH₃

        This equation shows the chemical formulae but it is not balanced. The law of mass conservation is not observed.

So, in order to comply with the law of mass conservation you adjust the coefficients as follow.

  • Balanced chemical equation: 3H₂ + N₂ → 2NH₃

        As you see, it was necessary to modify the coefficients. Now the law of conservation of mass is observed and you get the mole ratios:

  • 3 mol H₂ : 1 mol  N₂ : 2 mol NH₃

       

4 0
3 years ago
Write the balanced chemical equation for the following reaction. Phases are optional. Solid calcium chlorate decomposes to form
Tanya [424]

Answer:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Explanation:

1)<u> Word equation (given)</u>

  • <em>calcium chlorate (solid) → solid calcium chloride (solid)  + oxygen (gas)</em>

2) <u>Chemical formulae of the reactant and products</u>:

  • <em><u>Calcium chlorate</u></em><em>: </em>

The most common oxidation states of chlorine are -1, +1, +3, +5, +7.

The suffix ate in chlorate means that chlorine atom is with the third lowest oxidation state (counting only the positive states). So, this is +5.

The oxidation state of calcium is +2.

Hence, the chemical formula of calcium chlorate is Ca(ClO₃)₂

  • <u><em>Calcium chloride</em></u>

The suffix ide in chloride means that chlorine is with oxidation state -1. Again the oxidation state of calcium is +2.

Hence, the chemical formula of calcium chloride is CaCl₂

  • <u><em>Oxygen</em></u>

Oxygen gas is a diatomic molecule, so its chemical formula is O₂.

  • <u><em>Phases</em></u>

The symbols s and g (in parenthesis) indicate the solid and gas phases respectively.

3) <u>Chemical equation</u>:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + O₂ (g)

That equation is not balanced becasue the number of O atoms in the reactant side and in the product side are different.

4)<u> Balanced chemical equation:</u>

Add a 3 as coefficient in front of O₂(g), in the product side to balance:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Verify that all the atoms are balanced:

Atom    Reactant side      Product side

Ca             1                           1

Cl              2                          2

O              3×2 = 6                2×3 = 6

Conclusion: the equation is balanced and the final answer is:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)
5 0
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Q.1-

Given,

mass - 10grams

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density = 10/24

density = 0.416 g/cm³

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mass - 700grams

volume - 1100cm³

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How much energy (kJ) is required to change 0.18 mole of ice (s) at 0 C to water (l) at 0 C?
Dmitriy789 [7]

Answer:25,06 kJ of energy must be added to a 75 g block of ice.

ΔHfusion(H₂O) = 6,01 kJ/mol.

T(H₂O) = 0°C.

m(H₂O) = 75 g.

n(H₂O) = m(H₂O) ÷ M(H₂O).

n(H₂O) = 75 g ÷ 18 g/mol.

n(H₂O) = 4,17 mol.

Q = ΔHfusion(H₂O) · n(H₂O)

Q = 6,01 kJ/mol · 4,17 mol

Q = 25,06 kJ.

Explanation:

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2 years ago
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